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oee [108]
3 years ago
13

Someone help me please

Mathematics
1 answer:
vladimir1956 [14]3 years ago
3 0

Step-by-step explanation:

Hi,

You will have to move the pre-image 15 units to the right. You're also going to have to flip the image horizontally (kind of like flipping it across the x-axis) and after that, you're going to have to flip it so that it's facing the left side.

1) 15 units right

2) Flip-up

3) Flip to the left

Hope this helps :)

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a teacher promised a movie day to the class that did better, on average, on their test. The box plot shows the results of the te
natka813 [3]

The question is incomplete. The complete question is

A teacher promised a movie day to the class that did better, on average, on their test. The box plot shown in the below-mentioned figure shows the results of the test.

Which class should get the reward, and why?

- The 2nd-period class should get the reward. They have the highest score, a perfect 100.

- The 2nd-period class should get the reward. They have a higher median.

- The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

- The 4th-period class should get the reward. Their lowest score is an outlier and should be thrown out.

The box plot shown in the question provides the information that
In 2nd period the minimum of the data is 77, first quartile is 78, median of the data is 89, third quartile is 92 and the maximum of the data is 100.
Hence, the mean of the results of 2nd period is

\frac{77+78+89+92+100}{5}=87.2

In 2nd period the minimum of the data is 72, first quartile is 83, median of the data is 89, third quartile is 96 and the maximum of the data is 98.

Hence, the mean of the results of the 4th period is

\frac{72+83+89+96+98}{5}=87.6

Hence, obviously, the 4th period is having more mean.

Moreover, we can observe that if more of the marks are on the higher side the average will automatically be more. Hence, as the first and the third quartiles are more on the 4th-period, so the average marks for the 4th period must be better.

So, just by observing the box plot, we can give the statement that  "The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class. "

Therefore, the 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

Learn more about box plots here-

brainly.com/question/1523909

#SPJ10

6 0
2 years ago
Given that x:y=5:1 find 4x+5y:3x
kotykmax [81]

Answer:

5:3

Step-by-step explanation:

When the ratio says x:y=5:1, it means that x is 5 times greater than y. So, plug in 5 for x and 1 for y.

4(5)+5(1):3(5)

20+5:15

25:15 , if simplified then the ratio 5:3

6 0
4 years ago
4. If a Scooter goes 8 M/s, how fast does it go in KM/h?
Firlakuza [10]

Answer:

28.8 km/h

Step-by-step explanation:

I used the calculator, but I don't know any formulas for changing m/s km/h.

But I hope this helps!

7 0
3 years ago
Read 2 more answers
The three steps below were used to find the value of the expression [(-10+2)-1]+(2+3)​
brilliants [131]

Answer:

value of expression = 12

Step-by-step explanation:

[(-10+2)-1]+(2+3)​

=  [(8)-1]+(5)​              ∵according to PEMDAS, we first solve the Parenthesis

= (7)+(5)

= 12

8 0
4 years ago
1. Find the ratio of the width to the length of the rectangular swimming pool sketched below.
evablogger [386]
Ummm abcdefgh d maybe
4 0
3 years ago
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