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Orlov [11]
3 years ago
15

Cesium-137 has a half-life of about 30 years. A) Find the annual decay rate and round final result to 4 decimal places. B) Find

the continuous decay rate and round final result to 4 decimal places. C) How long will it take for a 10 gram sample to decay to 1 gram? Round to nearest year and interpret your result with a complete sentence. D) Complete this statement: as x goes to infinity, y goes to ___.
Mathematics
1 answer:
MrMuchimi3 years ago
8 0

Answer:

  • 0.0228
  • 0.0231
  • 100 years
  • 0

Step-by-step explanation:

The exponential equation for the fraction remaining after x years can be written as ...

  y = (1/2)^(x/30)

A) For x=1, the fraction remaining is ...

  y = (1/2)^(1/30) ≈ 0.97716 = 1 - 0.0228

Of the original amount, 0.0228 decays each year.

__

B) The continuous decay rate is the natural log of the growth factor, so is ...

  ln(0.97716) = -0.0231

The continuous decay rate is 0.0231 of the present amount (per year).

__

C) For y=.10 (1/10 of the original amount) we find x to be ...

  .1 = .5^(x/30)

  ln(.1) = (x/30)ln(.5) . . . . . take the natural log

  30ln(0.1)/ln(0.5) = x ≈ 100 . . . years

It will take 100 years for a 10-gram sample to decay to 1 gram.

__

D) As x goes to infinity, y goes to zero.

_____

The relationship between growth rate and growth factor is ...

  growth factor = 1 + growth rate

When the growth rate is negative, it is called a decay rate.

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What is the difference of the lengths of and ? use the value = 3.14, and round the answer to two decimal places. a. 1.25 units b
natulia [17]

The difference between the length of arc BD and CE is 1.57 units

<h3>Length of an arc</h3>

length of arc = ∅ / 360 × 2πr

where

  • r = radius
  • ∅ = central angle

Therefore,

BD = 45 / 360 × 2 × 3.14 × 6 = 1695.6 / 360 = 4.71 units

CE = 45 / 360 × 2 × 3.14 × 8 = 2260.8 / 360 = 6.28 units

Therefore, the difference between the length of arc BD and CE is as follows:

6.28 - 4.71 = 1.57 units

learn more on length of arc here: brainly.com/question/3984590

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1 year ago
21. Given that a line y = x passes through the origin and up to the right, what would the line y = mx look like if m = 1/2?
maks197457 [2]


a is the answer as the only change is the gradient being halved,

b would be if it was -1/2 and c would be1/2 x+1/2

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3 years ago
Is the statement below always,sometimes,or never true? Give at least two examples to
Musya8 [376]
Never true because if the product is 10 and the two numbers are 5 & 2 if you add them it won't give you 10 it will give you 7 so therefore the answer is never true
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FrozenT [24]

25

have a great day! :3

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Read 2 more answers
Helpp please please please
Harrizon [31]

Answer:

The ordered pairs in the <em>inverse of g = </em>{(-3, 5), (1, 4), (-2, 3), (0, 2)}

Step-by-step explanation:

Given that:

Relation <em>g</em> is given by the following table of values:

\begin{center}\begin{tabular}{ c c }x & y \\5 & -3 \\4 & 1\\3 & -2\\2 & 0\\\end{tabular}\end{center}

To find:

The ordered pairs in the inverse of relation <em>g.</em>

Solution:

First of all, let us learn about domain and range of a relation y=f(x).

Domain of a relation is the values of x that are given as input to the relation.

Range of a relation is the values of y\ or\ f(x) that come as the output of the relation.

When we take the inverse of any relation,

  • The Domain of Actual Relation becomes Range of the Inverse relation.
  • The Range of Actual Relation becomes Domain of the Inverse relation.

Now, let us have a look at the domain of given relation <em>g.</em>

Domain of g = set of values of x = {5, 4, 3, 2}

Range of g = set of values of y = {-3, 1, -2, 0}

Ordered pairs will be like (x, y)

Ordered pairs in <em> g </em>are: {(5, -3), (4, 1), (3, -2), (2, 0)}

The ordered pairs in the <em>inverse of g = </em>{(-3, 5), (1, 4), (-2, 3), (0, 2)}

8 0
3 years ago
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