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3 years ago

Solve for xx/6 + ≥ −2

Mathematics

1 answer:

Verizon [17]3 years ago

3 0

There is no answer because you didn’t put some thing after the + so it wouldn’t show nothing

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Look at the triangle below which of the following represents two of the angle measures of the triangle

Gelneren [198K]

Answer:

C. 60° and 80°

Step-by-step explanation:

Sum of triangle = 180°

Therefore,

8x + 4 + 6x - 2 + 10x + 10 = 180

Add like terms

8x + 6x + 10x + 4 - 2 + 10 = 180

24x + 12 = 180

24x = 180 - 12

24x = 168

x = 168/24

x = 7

Find each measure of the angles by substitute x = 7 into each expression

8x + 4 = 8(7) + 4 = 60°

6x - 2 = 6(7) - 2 = 40°

10x + 10 = 10(7) + 10 = 80°

The answer is 60° and 80°

6 0

3 years ago

I know how to do this but I just want to spend some points :)

Lunna [17]

Answer:

domain: all real numbers

range: y<-2

Step-by-step explanation:

I think its correct but already know the answer sooo yea

7 0

3 years ago

Which word is used to name the bold number?

prohojiy [21]

If 3 is the bold number then the answer is D. #TeamAlvaxic

7 0

3 years ago

As a sales person Jonathan is paid 50 per week +3% of the total Amount he sells. This week he wants to earn at least 100. Write

steposvetlana [31]

Answer:

The Inequality with integer coefficient for the total sales is $5000+3x\geq 10000$

Hence Jonathan should make total sales of at least 1667 to earn at least 100.

Step-by-step explanation:

Given:

Amount paid per week = 50

Addition amount = 3% of Total sales.

Let the Total sales be 'x'.

∴ Additional amount = $\frac{3}{100}x$

Amount he wants to earn this week $\geq$ 100

We need to write the inequality with integer coefficient for the total sales and also to find the total sales.

Solution:

We cans say that;

Amount paid per week plus Additional amount should be greater than or equal to Amount he wants to earn this week.

framing in equation form we get;

$50+\frac{3}{100}x\geq 100$

Now we will make the denominator common using LCM we get;

$\frac{50\times100}{100}+\frac{3}{100}x\geq 100$

$\frac{5000}{100}+\frac{3}{100}x\geq 100$

$\frac{5000+3x}{100}\geq 100$

Multiplying both side by 100 we get;

$100 \times\frac{5000+3x}{100}\geq 100\times 100\\\\5000+3x\geq 10000$

Hence The Inequality with integer coefficient for the total sales is $5000+3x\geq 10000$

On solving the above equation we get;

Subtracting both side by 5000 we get;

$5000+3x-5000\geq 10000-5000\\\\3x\geq 5000$

Dividing both side by 3 we get;

$\frac{3x}{3}\geq \frac{5000}{3}\\\\x\geq 1666.67$

Hence Jonathan should make total sales of at least 1667 to earn at least 100.

5 0

3 years ago

a company invested 25000 at an annual simple interest rate of 4.1% how much additional money must be invested at an annual simpl

Vlad [161]

We take interest+interest+interest to equal interest
0.041=4.1%(25000) the amount invested+0.056=interest they want=0.048 the total amount wanting to earn 4.8% and x is the added money to invest.
0.041(25000)+0.056x=0.048(25000+x)
1025+0.056x=1200+0.048x
subtract the 0.048 from both sides
1025+0.008x=1200+x
Subtract the 1025 from both sides
1025-1025+0.008=1200-1025+x
0.008x=175+x
Now divide 175 by 0.008
x=21,875

8 0

3 years ago

Solve for xx/6 + ≥ −2​

Solve for xx/6 + ≥ −2