Orders served by Latoya, Milan and Hong are 34, 24, 96 respectively.
<u>Solution:</u>
Given, Latoya, Milan, and Hong served a total of 154 orders Monday at the school cafeteria.
Let orders served by Latoya ne a, orders served by Milan be b and orders served by hong be c.
Then, a + b + c = 154 ⇒ (1)
Latoya served 10 more orders than Milan, ⇒ a = b + 10
Hong served 4 times as many orders as Milan. ⇒ c = 4b
We have to find how many orders did they each serve?
Now, substitute a and c values in (1)
(b + 10) + b + 4b = 154
b + b + 4b = 154 – 10
6b = 144
b = 24
Then, a = 24 + 10 = 34 and c = 4 x 24 = 96.
Hence, orders served by Latoya, Milan and Hong are 34, 24, 96 respectively.
take the log of both sides
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