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Degger [83]
3 years ago
14

What percent of 19 is 4.75?

Mathematics
1 answer:
IrinaK [193]3 years ago
8 0

Answer:

25%

Step-by-step explanation:

1. 4.75/19 = .25

2. .25 = 25%

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This year a softball coach raise $1200 for new equipment that is 4% less then he raise last year how much did he raise last year
charle [14.2K]
1200*96%
1200 \times 0.96
8 0
3 years ago
Help!!<br> What is the relationship between the corresponding angle bisectors BD and XZ?
Harrizon [31]

Answer:

XZ = 2.5 BD

Step-by-step explanation:

Comparing the two triangles,

\frac{BD}{BC} = \frac{XZ}{XY}

\frac{6}{8} = \frac{XZ}{20}

⇒ XZ = \frac{20*6}{8}

         = 15

XZ = 15

So that,

BD:XZ = 6:15

           = 1:2.5

Therefore, the relationship between BD and XZ is XZ = 2.5 BD.

8 0
3 years ago
Find the surface area of the rectangular prism
frutty [35]

Answer:82

Step-by-step explanation:

surface area=pxh + 2xb

p=perimeter of base

h=height

b=area of base

Perimeter of base=7+7+2+2=18

height=3

base area=7x2=14

surface area=18x3+2x14

Surface area=82

7 0
3 years ago
What is the solution of log4(2x-6)=2
Flauer [41]

Answer: x=11

Step-by-step explanation:

Remembert that, by definition:

log_b(x)=y → b^y=x

Then, you can rewrite log_4(2x-6)=2 in exponential form:

4^2=2x-6

Now you can solve for the variable "x":

Add 6 to both sides of the equation:

4^2+6=2x-6+6

22=2x

And finally you must divide both sides of the equation by 2, then:

\frac{22}{2}=\frac{2x}{2}\\\\x=11

3 0
3 years ago
1. Taylor needs to purchase a car. The car Taylor plans to purchase costs $10,000. Taylor has saved $2,000 to use as a down paym
Alexxandr [17]

Answer:

a. The amount Taylor will need to finance is $8,000

b. The amount Taylor pays as interest in one year is $400

Step-by-step explanation:

The given parameters of the financing for the car are;

The cost of the car Taylor plans to purchase, C = $10,000

The amount Taylor has saved to be used as down payment, S = $2,000

The interest rate of the credit Taylor is offered = 5%

The duration given for repayment of the loan = 5 years

a. To purchase the car, the amount Taylor will need to finance, 'P', is given as follows;

P = C - S

∴ P = $10,000 - $2,000 = $8,000

b. The amount of interest on the loan in one year, 'I', is given by the following formula;

I = \dfrac{P \times R \times T}{100}

Where;

I = The interest payed

P = The principal amount taken as loan = $8,000

R = The interest rate = 5% APR

T = The time period the interest is applied = 1 year

Plugging in the values, we get;

I = \dfrac{\$ \, 8,000 \times 5 \times 1}{100} = \$ \, 400

The interest Taylor will pay on the loan in one year, I = $4,00

7 0
3 years ago
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