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Andreyy89
3 years ago
8

What is the solution of log4(2x-6)=2

Mathematics
1 answer:
Flauer [41]3 years ago
3 0

Answer: x=11

Step-by-step explanation:

Remembert that, by definition:

log_b(x)=y → b^y=x

Then, you can rewrite log_4(2x-6)=2 in exponential form:

4^2=2x-6

Now you can solve for the variable "x":

Add 6 to both sides of the equation:

4^2+6=2x-6+6

22=2x

And finally you must divide both sides of the equation by 2, then:

\frac{22}{2}=\frac{2x}{2}\\\\x=11

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Under a dilation, the point (2, 6) is moved to (6, 18).
Sergio039 [100]

Answer:

3

Step-by-step explanation:

4 0
2 years ago
What is the greatest common factor for 84 and 56?
anzhelika [568]

Factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

<span>Factors of 84 are: 1, 2, 3, 4, 6, 7, 12, 14, 21, </span>28, 42, 84

The outside term multiplies by the outside term on the oposite side to equal the answer. 

Example:
Look at the factors of 84
84X1=84
2X42=84
3X28=84 
and so on!

6 0
3 years ago
Tell if the events are independent or dependent. Explain your reasoning.
MakcuM [25]
The answer is D. When flipping a coin, the probability of getting tails does not change no matter how many times you flip the coin. It will always be 1/2.
3 0
2 years ago
A ladder is leaning up against a house. The ladder is 20 feet long and the base of the ladder is 12 feet away from the house. Ho
MrRa [10]

Answer:

16 feet

Step-by-step explanation:

The length of the ladder=20 feet

Distance from the base of the ladder to the house = 12 feet

You will notice that a wall is vertical and the ladder makes an angle with the horizontal ground(making it the hypotenuse). This is a right triangle problem.

To find the how far up the house can the ladder can reach, we simply find the third side of the right triangle.

From Pythagoras theorem

Hyp^2=Opp^2+Adj^2\\20^2=12^2+Adj^2\\Adj^2=400-144\\Adj^2=256\\Adj=\sqrt{256}=16

The third side of the right triangle is 16. Therefore the ladder leans 16 feet from the ground.

8 0
3 years ago
Read 2 more answers
If C is between A and B, then answer the following if AB=40, AC= 2x+10, CB= 3x-5
Marat540 [252]

If C is between A and B, then, we can write the equation

AB = AC + CB


Substitute the value of AB and the expressions for AC and CB in terms of x.


40 = (2x+10)+(3x-5)


We can now solve for x.



40-10+5= 2x+3x



35=5x


Dividing by 5.


7=x


AB=40



AC=2(7)+10



AC=14+10



AC=24




BC=3(7)-5



BC=21-5


BC=16



6 0
3 years ago
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