Solve log x = 2 by changing it to exponential form.
2 answers:
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Y = 
x + 3
y = x - 4
Since both equations are equal to y, you can set the two values equal to each other and solve for x.
x + 3 = x - 4 Multiply both sides by 2
x + 6 = 2x - 8 Add x to both sides
6 = 3x - 8 Add 8 to both sides
14 = 3x DIvide both sides by 3
4
= x
Now, plug the x value into one of the original equations, I'll plug it into y = x - 4.
y = x - 4 Plug in the x value
y = 4 - 4 Subtract
y =
x = 4 and y =
y = x - 4
Since both equations are equal to y, you can set the two values equal to each other and solve for x.
x + 6 = 2x - 8 Add x to both sides
6 = 3x - 8 Add 8 to both sides
14 = 3x DIvide both sides by 3
4
Now, plug the x value into one of the original equations, I'll plug it into y = x - 4.
y = x - 4 Plug in the x value
y = 4
y =
x = 4