There are 3 ways of solving a simultaneous problem, substitution method, elimination method and Gauss-Jordan method. I'm gonna use the substitution method since it's easier and i think it would suit your level more.
First let's try solving for y since it's easier to start with.
Firstly we have to find an equation for x:
![x-2y=2\\x-2y+2y=2+2y\\x=2+2y](https://tex.z-dn.net/?f=x-2y%3D2%5C%5Cx-2y%2B2y%3D2%2B2y%5C%5Cx%3D2%2B2y)
Great, now we can use the substitution method to find the value of y using the first equation:
![2x+3y=11\\2(2+2y)+3y=11\\4+4y+3y=11\\7y=7\\y=1](https://tex.z-dn.net/?f=2x%2B3y%3D11%5C%5C2%282%2B2y%29%2B3y%3D11%5C%5C4%2B4y%2B3y%3D11%5C%5C7y%3D7%5C%5Cy%3D1)
Now we know that y=1 we can solve the first equation we made:
![x=2+2y\\x=2+2(1)\\x=4](https://tex.z-dn.net/?f=x%3D2%2B2y%5C%5Cx%3D2%2B2%281%29%5C%5Cx%3D4)
And the answer is ![x=4 , y= 1\\(4,1)](https://tex.z-dn.net/?f=x%3D4%20%2C%20y%3D%201%5C%5C%284%2C1%29)
Double check:
![2x+3y=11\\2(4)+3(1)=11\\8+3=11\\11=11\\\\x-2y=2\\(4)-2(1)=2\\2=2](https://tex.z-dn.net/?f=2x%2B3y%3D11%5C%5C2%284%29%2B3%281%29%3D11%5C%5C8%2B3%3D11%5C%5C11%3D11%5C%5C%5C%5Cx-2y%3D2%5C%5C%284%29-2%281%29%3D2%5C%5C2%3D2)
And that's our final answer! (4,1)
Answer:
Answer attached
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Answer:
the intersection of the triangle's three altitudes.
Step-by-step explanation:
hope this helped </3
Answer:
hi
Step-by-step explanation: