1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
podryga [215]
3 years ago
9

The drying times for a certain type of cement are normally distributed with a standard deviation of 30 minutes. A researcher wis

hes to estimate the mean drying time for this type of cement. Find the sample size needed to assure with 68.26% confidence that the sample mean will not differ from the population mean by more than 5 minutes.
a. 31
b. 26
c. 29
d. 38
e. 30
f. 27
g. 32
h. 36
Mathematics
1 answer:
IceJOKER [234]3 years ago
5 0

Answer:

h. 36

Step-by-step explanation:

For a 68.26% confidence, z = 1.0.

Standard deviation (s) = 30 minutes

The sample size needed to assure that the sample mean does not differ from the true mean by more than 5 minutes is given by:

5\geq z*\frac{s}{\sqrt n}\\\sqrt n\geq 1*\frac{30}{5}\\n\geq 36

The sample size needed is 36.

You might be interested in
A painting crew bought 30 gal of paint for a job. The crew members used 3 gal of paint per hour until they used all the paint.
zheka24 [161]

bottom right

Hope Your Thanksgiving Goes Well, Here's A Turkey

-TheKoolKid1O1

5 0
3 years ago
In 2012, there were about 313 million people in the United States, and just under 9 million of them had assets of $1 million or
zloy xaker [14]
New York has a density of millionaires more than twice that of the country as a whole. The density of millionaires is about the same for New York City as for the United States. Millionaires seem to prefer New York City to much of the rest of the United States. There is something in the water of New York City that encourages millionaires
3 0
3 years ago
A gold alloy contains 15 milligrams of gold for every 4 milligrams of copper. A jeweler uses 48 milligrams of copper to make the
Elina [12.6K]

Answer:

There are 180 milligrams of gold in the alloy

Step-by-step explanation:

because i know

7 0
3 years ago
What’s the answer too 3a - 5 = -14
GrogVix [38]

Answer:

well mostly the answer is welcome to help :) a = -15

4 0
3 years ago
Read 2 more answers
A parallelogram has sides 10m and 12m and an angle of 45°. Find the distance between the 12m-sides.
stich3 [128]

Answer:

The distance between 12m-sides is 5\sqrt{2}m.

Step-by-step explanation:

It is given that the parallelogram has sides 10m and 12m and an angle of 45°.

Draw an altitude from one 12m side to another 12 m side as shown in below figure.

The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.

Since angle C is acute angle therefore it must be 45 degree.

\sin\theta=\frac{perpendicular}{hypotenuse}

\sin C=\frac{BE}{BC}

\sin(45^{\circ})=\frac{d}{10}

\frac{1}{\sqrt{2}}=\frac{d}{10}

\frac{10}{\sqrt{2}}=d

\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=d

\frac{10\sqrt{2}}{2}=d

5\sqrt{2}=d

Therefore the distance between 12m-sides is 5\sqrt{2}m.

4 0
3 years ago
Other questions:
  • If 10% is deducted from bill, $58.50 remains to be paid. How much is original bill?
    12·2 answers
  • By what percent will the product of two numbers decrease if one of them is decreased by 25% and the other one is decreased by 50
    12·1 answer
  • What is -15.5t + 13.24 = -13.44 + 10.56 – 3.1t
    13·2 answers
  • Does anyone know the answer to this?
    6·1 answer
  • Is f(x)=1/3x+2 linear or exponential
    7·1 answer
  • 12.28 as a mixed number
    7·2 answers
  • A set of test scores is normally distributed with a mean of 78 and a standard deviation of 4.5. Dwayne scored 87 on the test. Wh
    6·2 answers
  • Can anyone help me with this please?
    8·1 answer
  • Find the 8th term of the geometric sequence whose common ratio is 3/2<br> and whose first term is 2.
    11·1 answer
  • Enter the sum in simplest form. pls answer I give brainliest
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!