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meriva
2 years ago
5

Please please help please please ASAP please I'm begging you please I have 10 minutes please y'all help please any ACE that can

help please

Mathematics
1 answer:
skad [1K]2 years ago
5 0

Answer:

6

Step-by-step explanation:

We know that the two quads are of similar and the ratio is 1:2, thus

AB/RS = 1/2

3/x = 1/2

x = 6

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Ratio of two complementary angles is 3:7. What's the measures of both angles
Advocard [28]
The total 'parts' of the ratio is 10 (3+7).
Complementary angles add to 90 degrees.
Divide 90 by 10 and you get 9.
Each 'part' is 9.
3:7 * 9 = 27:63
One angle is 27 degrees and the other is 63 degrees.
3 0
3 years ago
Mr. Jones jogs the same route each day. The amount of time he jogs is inversely proportional to his jogging rate.
german

Answer is option C

Mr. Jones jogs the same route each day. The amount of time he jogs is inversely proportional to his jogging rate.

time= \frac{k}{rate}

k is the constant of proportionality

We check with each option and identify which option gives us same K value

(a) 4 mph for 2.5 hours and 6 mph for 3.75 hours

2.5= \frac{k}{4} so k = 10

3.75= \frac{k}{6} so k = 22.5

K values are not same

(b) 3 mph for 2 hours and 4.5 mph for 3 hours

2= \frac{k}{3} so k = 6

3= \frac{k}{4.5} so k = 13.5

K values are not same

(c) 4 mph for 2.5 hours and 5 mph for 2 hours

2.5= \frac{k}{4} so k = 10

2= \frac{k}{5} so k =10

K values are  same .

Answer is option C


3 0
2 years ago
Read the following sentences from "The Third Bank of the River."
slega [8]
D) from childhood to adulthood my father was very honest and ope
4 0
3 years ago
Please help!! BRAINLIEST to correct answer!! I’m just confused by how to find two answers. I only found one.
GenaCL600 [577]
I have no clue but you could ask your teacher to help u with it no jk the answer is -7
3 0
2 years ago
Which shows all the like terms in the expression?<br> 4x-3+7X+1
vodomira [7]

Answer:

11x-2

Step-by-step explanation:

4x-3+7x+1

then

4x+7x-3+1

goes to

4x+7x-2

Answer: 11x-2

7 0
1 year ago
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