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irga5000 [103]
3 years ago
14

Try to to solve it please 2021 lets gooo​

Mathematics
2 answers:
ch4aika [34]3 years ago
5 0

1.When all the three cut outs of the angles A, B, C placed adjacent to each other at a point, then it forms a line forming a straight angle, i.e. 180°.

Flence, it is proved that the sum of the three angles of a triangle is 180°.

Therefore, ∠A + ∠B + ∠C =180

ValentinkaMS [17]3 years ago
4 0

Mark them brainliest

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Problem
Nikitich [7]

kong: 15% 15x100=1,500

Nolan:85 seconds 85x2=170

then when you multiple kong by 15 and 100 it gives you 1,500 however nolan did of the seconds 85x 2 gives you 170 . in conclusion Nolan did 15x2=30 . which means Nolan did 30 seconds.

3 0
3 years ago
Cellus
Solnce55 [7]

Answer:

<6

Step-by-step explanation:

Corresponding angles have the same matching corner.

<6 has the same matching corner as <2. <6 and <2 are congruent.

Therefore, it can be concluded that <6 corresponds to <2.

6 0
3 years ago
Kathy wants to buy a camera with an original price of $389. The camera is on sale with a 33% discount. What is the amount of dis
Verizon [17]

Answer:

$128.37

Step-by-step explanation:

Find 33% of 389:

389(0.33) = 128.37

The amount of the discount is $128.37

6 0
3 years ago
I need help what’s the answer to this Y = x + 1
UkoKoshka [18]

Answer: well, the answer can really be any two numbers, as long as y is one more than x. EXAMPLE: 16 = 15 + 1, 7 = 6 + 1, -54 = -55 + 1, etc

8 0
2 years ago
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
3 years ago
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