5x -3 = 12
5x -3 + 3 = 12 + 3 [Add 3 to each side]
5x + 0 = 15 [Evaluate]
5x/5 = 15/5 [Divide each side by 5]
1x = 3 [Evaluate]
The answer I get is the number 3.
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
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Step-by-step explanation:
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Ok so 12 in. = 1ft
210 in = 17.5 ft
35 in = about 2.9 ft
17.5/2.9 = approximately 6 ft.
I think the answer is 6 ft
At the same time 210/35 = 6, which would make the length 6 in., because area equals base times height, so you just divide, which would make it 1/2ft.
I would go with 6 in.
