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slega [8]
3 years ago
8

What are the coordinates of the vertex of the parabola with the equation y = x + 2x - 3?

Mathematics
1 answer:
loris [4]3 years ago
4 0

Answer:

<em>The coordinates of the vertex are (-1,-4).</em>

Step-by-step explanation:

<u>Equation of the Quadratic Function </u>

The vertex form of the quadratic function has the following equation:

y-k=a(x-h)^2

Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.

We are given the function:

y=x^2+2x-3

We must transform the equation above by completing squares:

The first two terms can be completed to be the square of a binomial. Recall the identity:

x^2+2xy+y^2=(x+y)^2

Thus if we add and subtract 1:

y=(x^2+2x+1)-3-1

Operating:

y=(x^2+2x+1)-4

The trinomial in parentheses is a perfect square:

y=(x+1)^2-4

Adding 4:

y+4=(x+1)^2

Comparing with the vertex form of the quadratic function, we have the vertex (-1,-4).

The coordinates of the vertex are (-1,-4).

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Express the function f(x) =3x^2-6x-18 in the form a(x + h)^2=k, where a, h and k are constants.Hence state the :
ololo11 [35]

Answer:

The minimum value of f(x) is -21 and it occurs at x = 1

Step-by-step explanation:

f(x) =3x^2-6x-18

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f(x) =3(x^2-2x)-18

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