Answer:
D. y = -5^x – 27
Step-by-step explanation:
Find the negative reciprocal of the slope of the original line and use the point-slope formula y
−
y
1
=
m
(
x
−
x
1
) to find the line perpendicular to −
x
+
5
y
=
14
.
y
=
−
5
x
−
27 PERPENDICULAAR
...................................................................................................................................................
Find the slope of the original line and use the point-slope formula y
−
y
1
=
m
(
x
−
x
1
) to find the line parallel to −
x
+
5
y
=
14
.
y
=
1
/5
x
−
1 PARALLEL
The complex solution of a quadratic equation are (- 2 + i ) and
(- 2 - i ).
What is Quadratic equation?
An algebraic equation of the second degree is called a quadratic equation.
Given that;
A quadratic equation is;
3x² = -12x - 15
Now, The equation is written as;
3x² + 12x + 15 = 0
Take 3 common, we get;
3 (x² + 4x + 5) = 0
x² + 4x + 5 = 0
Factorize the equation by using Sridharacharya Formula;
x = - 4 ± √4² - 4*1*5 / 2*1
x = -4 ± √16 - 20 / 2
x = - 4 ± √-4 / 2
Since, √-1 = i
x = -4 ± 2i / 2
x = - 2 ± i
It gives two values of x as;
x = - 2 + i
And, x = - 2 - i
Hence, The complex solution of a quadratic equation are (- 2 + i ) and
(- 2 - i ).
Learn more about the quadratic equation visit:
brainly.com/question/24334139
#SPJ1
Length: 2w-12
Area is length times width so (2w-12)*w
Or 2w^w-12w
The common factor is 7 so its
7(2x - 3)
Answer:
x = 2 is the correct answer :)
