I WILL GIVE BRAINIEST
2 answers:
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First we have to find the tangent line:
y - y o = f ` ( x o ) * ( x - x o )
f ` ( x ) = 10 x
y - 80 = 40 ( x - 4 )
y = 40 x - 160 + 80
y = 40 x - 80
There are 2 parts of this region:
A =
A = 40/3 + 320/3 - 320 + 320 - 40/3 + 80 - 160 = 320/3 - 240/3 = 80/3
y - y o = f ` ( x o ) * ( x - x o )
f ` ( x ) = 10 x
y - 80 = 40 ( x - 4 )
y = 40 x - 160 + 80
y = 40 x - 80
There are 2 parts of this region:
A =
A = 40/3 + 320/3 - 320 + 320 - 40/3 + 80 - 160 = 320/3 - 240/3 = 80/3
Solution :
Given
= weight of the first side
= 6 kg = 6000 g
= distance of the first weight from the triangle.
= 3 m = 300 cm
= distance of the first weight from the triangle.
= 600 cm
Let, = weight of the second side
So, x
=
x
or
= 3000 g
Therefore, the quantity that is used to replace the question mark in order to make the scale balance is 3000 g.
