Answer:
![\frac{-1}{x+3}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7Bx%2B3%7D)
Step-by-step explanation:
Hope this helps!
Answer:
B
Step-by-step explanation:
Answer:
1) 20%
2) Choice a.
Step-by-step explanation:
![P(t)=10000(0.2)^t](https://tex.z-dn.net/?f=P%28t%29%3D10000%280.2%29%5Et)
1)
is the population initially.
is the population after a year.
represents the population increase factor.
So let's evaluate that fraction:
![\frac{10000(0.2)^1}{10000(0.2)^0}](https://tex.z-dn.net/?f=%5Cfrac%7B10000%280.2%29%5E1%7D%7B10000%280.2%29%5E0%7D)
![\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2](https://tex.z-dn.net/?f=%5Cfrac%7B0.2%5E1%7D%7B0.2%5E0%7D%3D%5Cfrac%7B0.2%7D%7B1%7D%3D0.2)
0.2=20%
2) Let's figure out the population growth in terms of months instead of years.
![P(t)=10000(0.2)^{t}](https://tex.z-dn.net/?f=P%28t%29%3D10000%280.2%29%5E%7Bt%7D)
We want t to represent months.
A full year is 12 months, in a full year we have that ![P(1)=10000(0.2)^1=10000(0.2)=2000](https://tex.z-dn.net/?f=P%281%29%3D10000%280.2%29%5E1%3D10000%280.2%29%3D2000)
So we want a new P such that
since 12 months equals a year.
Let's look at the functions given to see which gives us this:
a) ![P(12)=10000(0.87449)^{12}=2000 \text{approximately}](https://tex.z-dn.net/?f=P%2812%29%3D10000%280.87449%29%5E%7B12%7D%3D2000%20%5Ctext%7Bapproximately%7D)
b) ![P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}](https://tex.z-dn.net/?f=P%2812%29%3D10000%280.87449%29%5E%7B12%2812%29%7D%3D0%20%5Ctext%7B%20approximately%7D)
c) ![P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}](https://tex.z-dn.net/?f=P%2812%29%3D10000%280.87449%29%5E%7B%5Cfrac%7B1%7D%7B12%7D%7D%3D9889%20%5Ctext%7Bapproximately%7D)
d) ![P(12)=10000(0.87449)^{12+12}=400 \text{approximately}](https://tex.z-dn.net/?f=P%2812%29%3D10000%280.87449%29%5E%7B12%2B12%7D%3D400%20%5Ctext%7Bapproximately%7D)
So a is the function we want.
Also another way to look at this:
where
is in years.
where
is in months.
And ![.2^\frac{1}{12}=0.874485 \text{approximately}](https://tex.z-dn.net/?f=.2%5E%5Cfrac%7B1%7D%7B12%7D%3D0.874485%20%5Ctext%7Bapproximately%7D)
Answer:
I believe the answer would be 20 miles max for one passenger.
Step-by-step explanation:
This is because if you create an equation out of this, knowing that only one passenger will be riding, you will get:
$3.00+$1.25x=$28 ($3 added too $1.25 times the number of miles (x) which equals the total amount you have ($28)).
x being the number of miles (so we need to calculate for x)
$3 + $1.25x = $28
-subtract 3 on both sides-
$1.25x=$28-$3
$1.25x=$25
-divide by 1.25 on both sides-
x=$25/$1.25
x=20 miles
Not sure if all calculations are correct, but I hope this helps :)!