3 years ago

Find the minimum or maximum value of f (x) = x2 - 6x + 13.

1 answer:

7 0

Minimum value is (3, 4)

It is the minimum value because the coefficient of x^2 is positive.

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scZoUnD [109]

It think it’s 6x...!

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3 years ago

abruzzese [7]

$\huge{\boxed{2 \sqrt{101}}}$

The distance formula is $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are the points.

Substitute in the points. $\sqrt{(2-4)^2+(-8-12)^2}$

Subtract. $\sqrt{(-2)^2+(-20)^2}$

Solve the exponents. $\sqrt{4+400}$

Add. $\sqrt{404}$

Now, we can simplify this square root just a little bit. $404$ has a square factor of $4$ . $\sqrt{404}=\sqrt{4}*\sqrt{101}$

The square root of $4$ equals $2$ . $\boxed{2 \sqrt{101}}$

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3 years ago

lubasha [3.4K]

Yes it does matter which way you subtract

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3 years ago

ella [17]

Answer:28 words in 3/2 of a minute

Step-by-step explanation:

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2 years ago

Elan Coil [88]

How you wrote it is kind of confusing but if I'm reading what you're saying right. There are 2028 . <span />

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3 years ago