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kykrilka [37]
2 years ago
14

A blueprint of a house shows a

Mathematics
1 answer:
prohojiy [21]2 years ago
3 0

Answer:

108

Step-by-step explanation:

3 ft. squared is 9 ft.

9x12=108

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Write the formula for the area of a triangle, A=1/2bh in terms of h. Find the height of a triangle when A = 18 in. squared and b
Elena L [17]

The height of the given triangle is  

5 0
3 years ago
Can I get help please and thank you
Ipatiy [6.2K]

9514 1404 393

Answer:

  a.  0.81

  b.  v = 28000(0.81^n)

  c.  2757.36

Step-by-step explanation:

a. The growth factor is 1 more than the growth rate. Here, the growth rate is -19% (per year), so the growth factor, the multiplier, is ...

  1 -0.19 = 0.81

__

b. The equation sets value equal to the original value multiplied by the growth factor to the power of the number of years:

  value = (original value) × (growth factor)^n

  v = 28000(0.81^n)

__

c. For n=11, this is ...

  v = 28000(0.81^11) ≈ 2757.36

The value of the truck after 11 years is about $2757.

6 0
3 years ago
Please help me out with this..............
Andrews [41]

Answer:

C

Step-by-step explanation:

when x=0, y=0, so B is impossible

when X=2, Y=1,

and thus C is correct

6 0
3 years ago
2x-5y<20 is solid or dotted and would you shade above or belowthe line?​
Kazeer [188]

Answer:

y>-4+2x/5

Step-by-step explanation:

5 0
2 years ago
A bacteria culture starts with 400 bacteria and grows at a rate proportional to its size. After 4 hours, there are 9000 bacteria
Kaylis [27]

Answer:

A) The expression for the number of bacteria is P(t) = 400e^{0.7783t}.

B) After 5 hours there will be 19593 bacteria.

C) After 5.55 hours the population of bacteria will reach 30000.

Step-by-step explanation:

A) Here we have a problem with differential equations. Recall that we can interpret the rate of change of a magnitude as its derivative. So, as the rate change proportionally to the size of the population, we have

P' = kP

where P stands for the population of bacteria.

Writing P' as \frac{dP}{dt}, we get

\frac{dP}{dt} = kP.

Notice that this is a separable equation, so

\frac{dP}{P} = kdt.

Then, integrating in both sides of the equality:

\int\frac{dP}{P} = \int kdt.

We have,

\ln P = kt+C.

Now, taking exponential

P(t) = Ce^{kt}.

The next step is to find the value for the constant C. We do this using the initial condition P(0)=400. Recall that this is the initial population of bacteria. So,

400 = P(0) = Ce^{k0}=C.

Hence, the expression becomes

P(t) = 400e^{kt}.

Now, we find the value for k. We are going to use that P(4)=9000. Notice that

9000 = 400e^{k4}.

Then,

\frac{90}{4} = e^{4k}.

Taking logarithm

\ln\frac{90}{4} = 4k, so \frac{1}{4}\ln\frac{90}{4} = k.

So, k=0.7783788273, and approximating to the fourth decimal place we can take k=0.7783. Hence,

P(t) = 400e^{0.7783t}.

B) To find the number of bacteria after 5 hours, we only need to evaluate the expression we have obtained in the previous exercise:

P(5) =400e^{0.7783*5} = 19593.723 \approx 19593.  

C) In this case we want to do the reverse operation: we want to find the value of t such that

30000 = 400e^{0.7783t}.

This expression is equivalent to

75 = e^{0.7783t}.

Now, taking logarithm we have

\ln 75 = 0.7783t.

Finally,

t = \frac{\ln 75}{0.7783} \approx 5.55.

So, after 5.55 hours the population of bacteria will reach 30000.

6 0
3 years ago
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