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kykrilka [37]
3 years ago
14

A blueprint of a house shows a

Mathematics
1 answer:
prohojiy [21]3 years ago
3 0

Answer:

108

Step-by-step explanation:

3 ft. squared is 9 ft.

9x12=108

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1/6% of 295 help ASAP
iVinArrow [24]

Answer: 0.49

Step-by-step explanation:

1/6% X 295 = 0.00167 X 295

= 0.492~0.49

5 0
3 years ago
Meghan also wants to walk to get some exercise, rather than going to the gym. She decides to walk along arc AB. How far will she
Karo-lina-s [1.5K]

Answer:

π*AB

Step-by-step explanation:

I m not quite sure about your question because it is lack of details.

However, as my per understanding, Meghan decides to walk along arc AB it means she walks an interval equal to the circumference of the circle AB.

So, apply the formula in caculating the circumference of the circle, we have:

π*d = π*AB

So, she walk a π*AB distance.

8 0
3 years ago
Write a simplified polynomial expression in standard form to represent the area of the rectangle below.
Stells [14]

Answer:

5x^{2} -18x-8

Step-by-step explanation:

The formula for area of a rectange is lw, where l is length and w is width.  Since x-4 and 5x+2 are the sides, we can multiply them together to give us the area.  We do (x-4)(5x+2).  We use the FOIL method (First Outside Inside Last) and get 5x^2-18x-8.

7 0
3 years ago
3 Valley Video charges a $15 annual
djyliett [7]

Answer:

x = 28

Step-by-step explanation:

15 + 3x = 99

-15. -15

<u>3x</u> = <u>84</u>

3. 3

x = 28

4 0
3 years ago
An arrow is shot vertically upward at a rate of 240 feet per second from ground level. Use the projectile formula to determine w
Juli2301 [7.4K]

Answer:

After 14.92 seconds, the arrow hits the ground.

Step-by-step explanation:

Given:

Initial velocity of the arrow is, u=240\ ft/s or 73.152\ m/s

The arrow goes up and come back to the same starting position. So, initial position is same as that of final position.

Therefore, displacement of the arrow is 0 m.

The displacement of the arrow is given as:

s=ut-\frac{1}{2}gt^{2}   (equation 1)

Plug all value in equation 1 and solve for t

0=73.152\timests t-\frac{1}{2} \times9.8 \times t^{2}

0=73.152\timests t-4.9 \times t^{2}

0=t(73.152-4.9 \times t)

73.152-4.9\times t=0     where t\neq 0

4.9\times t=73.152

t=\frac{73.152}{4.9}= 14.92\ s

∴ After 14.92 seconds, the arrow hits the ground.

5 0
3 years ago
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