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aksik [14]
3 years ago
13

The figure shows a grapefruit half. The radius to the outsideof the rind is 5 cm. The radius to the inside of the rind is 4 cm.T

he edible part ofthe grapefruit is divided into 12 equal sections.Find the volume of the half grapefruit and the volume of one ediblesection. Give your answers in terms of .
Mathematics
1 answer:
Marysya12 [62]3 years ago
5 0

Answer:

the volume of the inside of half grapefruit is ( 128/3) pi the volume of 1 of the 12 segments is (32/9) pi

Step-by-step explanation:

The volume of half a sphere (hemisphere) is (2/3) pi r^3  

(2/3) 4^3 pi = (2/3)(64)pi = (128/3) pi  -

The volume of one of the 12 segements is the answer divided by 12

128/36 pi  =( (32/9) pi

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10x + .0085x = 280000
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Answer:

x = 27976.22021

Step-by-step explanation:

10x + .0085x = 280000

Combine like terms

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Divide by 10.0085 on each side

10.0085x /10.0085= 280000/10.0085

x = 27976.22021

6 0
4 years ago
An athletic field is a 48 yd​-by-96 yd ​rectangle, with a semicircle at each of the short sides. A running track 20 yd wide surr
MA_775_DIABLO [31]

The distance would be equal to 2 times the longest side of the rectangle plus twice the shortest side multiplied by pi / 2 for the semicircle, that is:

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D = 192 + pi * 48

This shorter side, which starts at 48, will expand each time by two more in proportion to 20 of the running track between 8 than the number of divisions, that is, 2 * (20/8) = 5

In other words, there are 8 distances, like this:

D1 = 192 + 3.14 * 48 = 342.72 yd

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D8 = 192 + 3.14 * (48 + 35) = 452.62 yd

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3 years ago
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Step-by-step explanation:

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