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tankabanditka [31]
3 years ago
8

Find f(3x-2) for f(x)=x-5

Mathematics
1 answer:
serious [3.7K]3 years ago
4 0

Answer:

f(x)=x–5

f (3x–2) = (3x–2) –5

f (3x–2) = 3x–7

I hope I helped you^_^

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(-9x²-2x) - (-9x²-3x) = (-9x²-2x) +(9x²+3x) = -9x²-2x+9x²+3x = (-9x²+9x²)+(-2x+3x) = x
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Justin is 2 years older
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Answer:
5

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1/4 of 12 = 3
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2 years ago
W+3 3/8=1 5/6 what is the answer
Annette [7]

W + 3 3/8 = 1 5/6;

W = 1 5/6 - 3 3/8;

W = 11/6 - 27/8;

W = 11/(2*3) - 27/(2*4);

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W = -37/24 = -1 13/24;

5 0
3 years ago
Line AB contains points A(4, 5) and B(9, 7). What is the slope AB
MatroZZZ [7]
For the answer to the question, what is the slope AB if l<span>ine AB contains points A(4, 5) and B(9, 7)?
The</span> answer <span>to </span>this question is 2/5.
I hope my answer helped you. Feel free to ask more questions. Have a nice day!
4 0
3 years ago
Read 2 more answers
Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distribut
defon

Answer:

0.8665 = 86.65% probability that the sample mean would be at least $39000

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125:

This means that n = 125, s = \frac{7320}{\sqrt{125}} = 654.72

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{654.72}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

0.8665 = 86.65% probability that the sample mean would be at least $39000

4 0
3 years ago
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