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zalisa [80]
3 years ago
13

Suppose there are 3 concerts at this hall next week, and the total attendance will be 5,500. Use a percent expression to predict

the number of these attendees who will leave a concert early next week.
Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
4 0

Answer:1,833

Step-by-step explanation: 5,500 divided by 3 is 1,833. Correct me if I’m wrong I think that’s what your doing

Zielflug [23.3K]3 years ago
4 0
1.833 hopes this helps
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For what value of r is the parallelogram a rhombus
Gre4nikov [31]

Answer:

9

Step-by-step explanation:

7r+18=r²

r²-7r-18=0

factorizing

r²+2r-9r-18=0

r(r+2)-9(r+2=0

(r-9)(r+2)=0

r-9=0

r=9

check

(r²)=(9*9)=81

7r+18=7(9) + 8=81

5 0
3 years ago
Combine like terms 7a - a+ 16 = ?
dexar [7]
6a+16

Explanation:
If there's just a variable, there's an understood 1 in front of it. So what that really says is:

7a-1a+16

So, you combine the a's. 7a minus 1a is 6a. Same as 7-1,but you have a variable stuck on the end of it.

6a+16

:^)
4 0
3 years ago
Read 2 more answers
How could you check your work in problem 4 ? Describe each step​
tamaranim1 [39]

Answer:

tiger algebra

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7 0
3 years ago
Determine if the given differential equation is exact (e^2y-y cos xy)dx+(2xe^2 y-cos xy+2y)dy=0
rewona [7]
\dfrac\partial{\partial y}\left[e^{2y}-y\cos xy\right]=2e^{2y}-\cos xy+xy\sin xy

\dfrac\partial{\partial x}\left[2xe^{2y}-y\cos xy+2y\right]=2e^{2y}+y\sin xy

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7 0
3 years ago
Find the standard deviation of the following data. Round your answer to one decimal place. x 0 1 2 3 4 5 P(X
lbvjy [14]

Answer:

<em></em>\sigma = 1.8<em></em>

<em></em>

Step-by-step explanation:

Given

\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4}& {5} \ \\ P(x) & {0.2} & {0.1} & {0.1} & {0.2} & {0.2}& {0.2} \ \end{array}

Required

The standard deviation

First, calculate the expected value E(x)

E(x) = \sum x * P(x)

So, we have:

E(x) = 0 * 0.2 + 1 * 0.1 + 2 * 0.1 + 3 * 0.2 + 4 * 0.2 + 5  * 0.2

E(x) = 2.7

Next, calculate E(x^2)

E(x^2) = \sum x^2 * P(x)

So, we have:

E(x^2) = 0^2 * 0.2 + 1^2 * 0.1 + 2^2 * 0.1 + 3^2 * 0.2 + 4^2 * 0.2 + 5^2  * 0.2

E(x^2) = 10.5

The standard deviation is:

\sigma = \sqrt{E(x^2) - (E(x))^2}

\sigma = \sqrt{10.5 - 2.7^2}

\sigma = \sqrt{10.5 - 7.29}

\sigma = \sqrt{3.21}

<em></em>\sigma = 1.8<em> --- approximated</em>

5 0
3 years ago
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