Answer:
Step-by-step explanation:
The probability of getting one even and one odd is the sum of probability of getting even and of getting odd and even. Since there are 3 even or odd on each die out of six numbers you have
P(EO)(3/6)(3/6)=1/4 and P(OE)=(3/6)(3/6)=1/4 so 1/4+1/4= 1/2
or you can find the probability of getting two odds or two evens and subtract that from 1
P(EE)=(3/6)(3/6)=1/4, P(OO)=(3/6)(3/6)=1/4
P(EO)=1-1/4-1/4=1/2
To reduce<span> a </span>fraction to lowest terms<span> (also called its simplest form), divide both the numerator and denominator by the GCD. For example, 2/3 is in </span>lowest<span> form, but 4/6 is not in </span>lowest<span> form (the GCD of 4 and 6 is 2) and 4/6 can be expressed as 2/3.
38/80= 19/40</span>
Answer: See attached images
Step-by-step explanation:
For third period:
Minimum = 67
1st Quartile: 79.5
Median/2nd Quartile: 85
3rd Quartile: 90.5
Maximum = 99
I've attached the image for this class's box plot.
For Sixth Period:
Minimum = 70
1st Quartile: 79.5
Median/2nd Quartile: 88
3rd Quartile: 90.5
Maximum = 95
I've also attached the image for this class's box plot
Answer: 56
Step-by-step explanation:
