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kondaur [170]
3 years ago
15

Which of the following mortgage options will not have a PMI requirement?

Mathematics
2 answers:
uranmaximum [27]3 years ago
6 0
I think the answer c
melomori [17]3 years ago
4 0
The correct answer was C.
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Do you know what 2/9 x 3 is?
ohaa [14]

Answer:

answer =  \frac{2}{3}

\frac{2}{9}  \times  \frac{3}{1}  \\   =  \frac{6}{9}  =  \frac{2}{3}

7 0
3 years ago
Read 2 more answers
Which qoutients are equivalent to -2/3?
Mice21 [21]
The answers are : A and C
3 0
3 years ago
For what values of m does the graph of y = 3x^2+ 7x + m have two x-intercepts?
qaws [65]

Answer:

m < 49/12

Step-by-step explanation:

The portion of the quadratic formula under the square root sign is the discriminant.

If the discriminant is > 0 then there are two real roots.

b² -4ac > 0

-----------------------------

7² - 4(3)m > 0

49 - 12m > 0

Subtract 49 from both sides

-12m > -49

Divide both sides by -12

(when multiplying or dividing by a negative the inequality must be reversed)

m < 49/12

8 0
3 years ago
What is the solution of this proportion 4/9 = 6/d
Alchen [17]

Answer:

d = 2/27

Remember that when a variable is times with a number you <u>divide</u> the number on both sides.

When a variable is divided by a number, you <u>multiply</u> the number on both sides.

Hope this helps you and thank you !!

4 0
3 years ago
Write a rule to describe the function shown. x y −6 −4 −3 −2 0 0 3 2 y equals start fraction two over three end fraction x y equ
sertanlavr [38]

Answer:

y=\frac{2}{3} x (y equals start fraction two over three end fraction x)

Step-by-step explanation:

Lest's organize the table values of our function first:

x    y

-6  -4

-3  -2

0   0

3   2

The simplest kind of of function is a linear function of the form y=mx+b where m is the slope and b is the y-intercept. Let's us check if our function is a linear one finding its equation and checking that all points are in the line.

The first step to find a linear equation is find the slope of the line; to do it, we are using the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}

where

m is the slope of the line

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

We know from our table that the first and second points are (-6, -4) and (-3, -2) respectively, so x_1=-6, y_1=-4, x_2=-3, and y_2=-2.

Replacing values:

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{-2-(-4)}{-3-(-6)}

m=\frac{-2+4}{-3+6)}

m=\frac{2}{3)}

Now that we have the slope of our line we can use the point slope formula to complete our linear function:

y-y_1=m(x-x_1)

where

m is the slope

(x_1,y_1) are the coordinates of the first point

Replacing values:

y-y_1=m(x-x_1)

y-(-4)=\frac{2}{3)}(x-(-6))

y+4=\frac{2}{3)}(x+6)

y+4=\frac{2}{3} x+4

y=\frac{2}{3} x+4-4

y=\frac{2}{3} x

Now, to check if our function is valid, we can either check if each point satisfies the rule y=\frac{2}{3} x, or we can graph it and check if each lies is in the graph.

Let's check both:

We already know that points (-6, -4) and (-3, -2) satisfy the rule (after all, those were the point we used to came out with the rule in the first place), so we just need to check the points (0, 0) and (3, 2)

- For (0, 0):

y=\frac{2}{3} x

0=\frac{2}{3}(0)

0=0

The point satisfies the rule.

- For (3, 2):

y=\frac{2}{3} x

2=\frac{2}{3} (3)

2=2

The point satisfies the rule.

Since all the points of our table satisfies the rule y=\frac{2}{3} x, we can conclude that the rule describing the function shown is y=\frac{2}{3} x.

4 0
3 years ago
Read 2 more answers
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