Which of the following mortgage options will not have a PMI requirement?

Please help!!!!!!!!!!!

AVprozaik [17]

I can’t view the photo.

7 0

3 years ago

The pyramid shown has a height of 14 inches and a base area of 60 in2. Find the volume of the pyramid.

Kamila [148]

Volume of pyramid is $280 in^{3}$ .

The pyramid has a height 14 inches and a base area of 60 in2.

What is volume?

Volume is a three - dimensional quantity that is used to measure the capacity of a solid shape.

Volume of the pyramid = $Area base$ X $\frac{height}{3}$

= $60.\frac{14}{3}$

= $280$ $in^{3}$

So the volume of pyramid = $280$ $in^{3}$

Learn more about the Volume visit:

https://brainly.in/question/609711

#SPJ1

8 0

1 year ago

8.45 as a mixed number

Vlad [161]

A mixed number is a combination of a whole number and a fraction, so in this case we have 8 as the whole part and 0.45 as the fraction, 0.45 is equal to 45/100, and that fraction can be simplified as well, lets see:
8.45 = 8 45/100
= 8 9/20

4 0

2 years ago

Given the trinomial 2x*2 + 4x + 4, predict the type of solutions. a. Two rational solutions b. One rational solution c. Two irra

OverLord2011 [107]

Answer:

d. Two complex solutions

Step-by-step explanation:

We have been given a trinomial $2x^2+4x+4$ and we are supposed to predict the type of solutions of our given trinomial.

We will use discriminant formula to solve for our given problem.

$\text{Discriminant}=b^2-4ac$ , where,

$a =\text{Coefficient of }x^2$ ,

$b =\text{Coefficient of }x$ ,

$c =\text{Constant }$

Conclusion from the result of Discriminant are:

$D$

$D=0\text{ means one real zero with of multiplicity two}$

$D>0\text{ means two distinct zeroes}$

Upon substituting our given values in above formula we will get,

$\text{Discriminant}=4^2-4*2*4$

$\text{Discriminant}=16-32$

$\text{Discriminant}=-16$

Since our discriminant is less than zero, therefore, out given trinomial will have two complex solutions and option d is the correct choice.

3 0

3 years ago

Read 2 more answers

A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters

natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that $p = 0.7$

20 eligible voters were randomly selected from the population of all eligible voters.

This means that $n = 20$

What is the probability that fewer than 11 of them will vote?

This is:

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308$

$P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120$

$P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039$

$P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010$

$P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002$

$P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0$

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479$

0.0479 = 4.79% probability that fewer than 11 of them will vote

8 0

3 years ago