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3 years ago

Which of the following mortgage options will not have a PMI requirement?

Mathematics

2 answers:

uranmaximum [27]3 years ago

6 0

I think the answer c

melomori [17]3 years ago

4 0

The correct answer was C.

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Pls help me find the sum ❣️

Natasha2012 [34]

Answer:

Step-by-step explanation:

4 0

3 years ago

Find the slope of the line through (–9, –10) and (–2, –5). A. –five-sevenths B. seven-fifths C. five-sevenths D. –negative seven

vredina [299]

Answer:

C 5/7

Step-by-step explanation:

We can find the slope of a line using

m = (y2-y1)/(x2-x1)

= (-5 - -10) /(-2 - -9)

= (-5 +10)/(-2+9)

5/7

8 0

3 years ago

Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t

Neporo4naja [7]

Answer:

$V=61.66$

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

$V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx$

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

$f(x)=g(x)\\ln(x)=\frac{1}{2}x-2$

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

$R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\$

and by replacing in the integral we have

$V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\$

$V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]$

and by evaluating in the limits we have

$V=61.66$

Hope this helps

regards

3 0

3 years ago

A regular Pentagon with sides 40cm what is the perimeter

grigory [225]

Perimeter = namely the length of outside bordering,

well, this is a PENTAgon, or PENTA=5 or namely 5 sides, is regular so each side is the same length, so we have a polygon with 5 sides each measuring 40cm, well, its perimeter is just 40+40+40+40+40 = 200.

7 0

3 years ago

How many ridges would there be on $10 worth of quarters?

tresset_1 [31]

Answer:

4760

Step-by-step explanation:

First you find out how many are in a dollar so you do

119*4 which is 476

Then because there is $10 you need to do

476 * 10 which would be 4760

4 0

2 years ago

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