Lets say the width is W and the length is L,
So its W * L = 196
but we also know W*4 = L
which means we can substitute L for W * 4 so our equation will be
W*W*4 = 196
W*W = 49
W= 7
Answer:
The length of side BC is 2.8 units
Step-by-step explanation:
* Lets revise how to find the distance between two points
- If there are two points their coordinates are (x1 , y1) and (x2 , y2),
then we can find the distance between them by this rule:
d = √[(x2 - x1)² + (y2 - y1)²]
- Now lets solve the problem
∵ B = (3 , 3)
∵ C = (5 , 1)
- To find the length of BC use the rule of the distance above
- Let point B is (x1 , y1) and point C is (x2 , y2)
∵ x1 = 3 and x2 = 5
∵ y1 = 3 and y2 = 1
∴ BC = √[(5 - 3)² + (1 - 3)²]
∴ BC = √[(2)² + (-2)²]
∴ BC = √[4 + 4] = √8 = 2.8 units
* The length of side BC is 2.8 units
Pretty low, it’s exactly 0.175
Answer:
(-5, -7) and the x-axis
Step-by-step explanation:
when looking for a point that is 7 points away, we are looking for a difference of 7 in either the x-value or the y-value.
[remember: a point is written as (x, y) ]
We know that the x-value is -7, meaning that it is 7 units under the x-axis (meaning that it is 7 units away)
We know that our point, (2 , -7) has the same y-value as (-5, -7), so we are looking for a change in x. The difference (which is the change) between:
-5 and 2 is 7
(2 - (-5) = 2 + 5 = 7)
so, both the x-axis and the point (-5, -7) are 7 units away from (2, -7)
(the other point (-7, 7) is not near (2 , -7) at all--they have a larger difference on both the y-values, the x-values, and the length of if you made a diagonal line)
(I've attached an image to help you visualize what we're doing)
hope this helps!!