The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).
<h3>How to analyze quadratic equations</h3>
In this question we have a graph of a <em>quadratic</em> equation translated to another place of a <em>Cartesian</em> plane, whose form coincides with the <em>vertex</em> form of the equation of the parabola, whose form is:
g(x) = C · (x - h)² - k (1)
Where:
- (h, k) - Vertex coordinates
- C - Vertex constant
By direct comparison we notice that (h, k) = (5, 1) and C = 1. Now we proceed to check if the points (x, y) = (2, 10) and (x, y) = (8, 10) belong to the parabola.
x = 2
g(2) = (2 - 5)² + 1
g(2) = 10
x = 8
g(8) = (8 - 5)² + 1
g(8) = 10
The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).
To learn more on parabolae: brainly.com/question/21685473
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The answer is 4/3 and I checked two times
The common factor in both terms is 10<span />
Answer:
Look Down
Step-by-step explanation:
1) x=9
2) x=12
3) x=12
4) x=12
5) x=11
6) x=11
Answer:
0.1 or 1/10
Step-by-step explanation:
The digits 4, 5, 6, 7 and 8 are randomly arranged to form a three digit number, where the digits are not repeated.
This is question of permutation.
Imagine this sum as; there are 3 boxes(blank spaces for digits) and 5 different fruits(digits) are to be put in these boxes, where a box can hold a maximum of only 1 fruit. The number of such permutations are: ⁵P₃
By formula (a! is factorial a):
ᵃPₙ 
⁵P₃ 
⁵P₃ 
⁵P₃ 
⁵P₃= 60
This is the total count of possible numbers that can be formed.
Now, for a number to be greater than 800 and even; first digit should necessarily be 8. Last digit can be 4 or 6. Using these conditions, there are 6 possibilities. 854, 864, 874, 846, 856, 876 are the numbers.
The probability that number is even and greater than 800 is:


