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Zanzabum
3 years ago
14

There is a right angled triangle. 30cm, 8.4cm and X. work out the value of x​

Mathematics
1 answer:
Bumek [7]3 years ago
4 0

Answer:

The Answer to the question is 28.8.

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The Jayden family eats at a restaurant that is having a 15% discount promotion. Their meal costs $78.25 before the discount, and
soldi70 [24.7K]

Answer:

$82.16

Step-by-step explanation:

78.25 * .20 = 15.65 as a tip,

78.25 *.15 = 11.74 as the discount, subtract from initial value:

78.25 - 11.74 = 66.51

then add the tip: 15.65 + 66.51 = $82.16

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3 years ago
PLEASE HELP WILL MARK BRAINLY <br><br> (ATTACHED)
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uum, Virus??

Step-by-step explanation:

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4 0
3 years ago
At a college campus, random drug tests are carried out to prevent use of prohibited drugs by athletes. Of all the athletes on ca
saw5 [17]

Answer:

a) 0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

b) 0.2693 = 26.93% probability that this drug user never used the prohibited drug.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

A. If an athlete is selected at random, what is the probability that athlete will test positive for prohibited drug use?

100 - 5 = 95% of 8%

100 - 13 = 87% of 17%

11% of 75%

So

p = 0.95*0.08 + 0.87*0.17 + 0.11*0.75 = 0.3064

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

B. If an athlete tests positive after a drug test, what is the probability that this drug user never used the prohibited drug?

Conditional Probability

Event A: Tests Positive

Event B: Never used the drug.

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use

This means that P(A) = 0.3064

Probability of testing positive while never using the drug.

11% of 75%. So

P(A \cap B) = 0.11*0.75 = 0.0825

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0825}{0.3064} = 0.2693

0.2693 = 26.93% probability that this drug user never used the prohibited drug.

8 0
3 years ago
Kira earned $7 mowing her neighbor's lawn for of an hour. What is her hourly rate? ​
Pavel [41]

Answer:

$7/hr

Step-by-step explanation:

6 0
3 years ago
Both expressions -3- (-7) and -7- (-3) involve the
Gelneren [198K]

Answer:

-3-(-7)=4 ,-7-(-3)=-4

Step-by-step explanation:

+ × += +

- × - = +

4 0
3 years ago
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