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kherson [118]
3 years ago
8

Help me please ............

Mathematics
2 answers:
sergeinik [125]3 years ago
8 0

Answer: 3

Step-by-step explanation:

3 + (-4) = -1

galina1969 [7]3 years ago
4 0

Answer:

Step-by-step explanation:

3+-4=-1

on the number line you can see that if you start at 3, go left 4 paces (-4) you land at -1

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Find <br><br>sin 22 1/2<br> °<br>please help​
Georgia [21]

Answer:

0.69465837 is the answer

7 0
3 years ago
Someone help me with this.
Mandarinka [93]

Answer:

2x² + 13x + 15

Step-by-step explanation:

| 2x | 3

x | 2x*x = 2x² | 3*x = 3x

5 | 2x*5 = 10x | 3*5 = 15

We have, 2x² + 3x + 10x + 15

Combining like terms, we would have the final expression as:

2x² + 13x + 15

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3 years ago
8^2+4−12 how do I factor this out.
lara [203]
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6 0
3 years ago
Simplify 2(3-2i)+5(1+i)
Kipish [7]
11+i
that’s the answer hope it helps:)
7 0
4 years ago
Given: y" - 2y' = 6t + 5e^2t. Find the correct form to use for y_p if the equation is solved using Undetermined coefficients. Do
const2013 [10]

Answer:

y_p=A+Bt+Ce^{2t}

Step-by-step explanation:

Given: y'' - 2y' = 6t + 5e^{2t}.

we need to find the correct form for y_p if the equation is solve using undetermined coefficients.

A first order differential equation \frac{\mathrm{d} y}{\mathrm{d} x}=f\left ( x,y \right ) is said to be homogeneous if f(tx,ty)=f(x,y) for all t.

Consider homogeneous equation y''-2y'=0

Let y=e^{rt} be the solution .

We get (r^2-2r)e^{rt}=0

Since e^{rt}\neq 0, r^2-2r=0.

So, we get solution as y_c=c_1+c_2e^{2t}

As constant term and e^{2t} are already in the R.H.S of equation

y" - 2y' = 6t + 5e^{2t}, we can take y_p as y_p=A+Bt+Ce^{2t}

6 0
4 years ago
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