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Whitepunk [10]
3 years ago
11

What is the slope of the line that passes through the points (-8,3)

Mathematics
1 answer:
IceJOKER [234]3 years ago
4 0

Answer:

Undifined

Step-by-step explanation:

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Select ALL the expressions that are equal to 3(n+4) *
telo118 [61]

Answer:

B and F

Step-by-step explanation:

8 0
3 years ago
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What is 4 (x-y) - 3 (x-y) ?
Anettt [7]

Answer: x+y

Step-by-step explanation: 4x-4y-3x-3y

4x-3x is x

4y-3y is y

7 0
2 years ago
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How many feet are in 100meters
77julia77 [94]

Answer: 328 feet, 1 inch

Step-by-step explanation:

3.281 feet makes 1 meter

To solve the question, Multiply the value by 3.281:

100 meters = 100 x 3.281 feets

=328.1 feet

I hope this helps.

5 0
3 years ago
What are the zeros of the function f(x) = x2 + 8x +4, expressed in simplest radical form?
Elanso [62]

Answer:

x = - 4 ± 2\sqrt{3}

Step-by-step explanation:

Given

f(x) = x² + 8x + 4

To find the zeros let f(x) = 0, that is

x² + 8x + 4 = 0 ( subtract 4 from both sides )

x² + 8x = - 4

To solve using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(4)x + 16 = - 4 + 16

(x + 4)² = 12 ( take the square root of both sides )

x + 4 = ± \sqrt{12} = ± 2\sqrt{3} ( subtract 4 from both sides )

x = - 4 ± 2\sqrt{3}

Thus the zeros are

x = - 4 - 2\sqrt{3} and x = - 4 + 2\sqrt{3}

5 0
3 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
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