Answer:
No
Step-by-step explanation:
x⁵ + 2x³ + x - 1 -> degree of the polynomial is 5
So, when x⁵ is divided by x³, the quotient should be x⁵⁻³ = x².
So, x³ - 3x + 1 cannot be a quotient
Answer:
Linear. While all linear equations produce straight lines when graphed, not all linear equations produce linear functions. In order to be a linear function, a graph must be both linear (a straight line) and a function (matching each x-value to only one y-value).
Y = mx + b
slope(m) = -3/4
(3,3)....x = 3 and y = 3
now we sub and find b, the y int
3 = -3/4(3) + b
3 = -9/4 + b
3 + 9/4 = b
12/4 + 9/4 = b
21/4 = b.....or 5.25 for graphing purposes
so ur equation is : y = -3/4x + 21/4
ur y int = (0,21/4) or (0,5.25)
ur x int can be found by subbing in 0 for y and solving for x
y = -3/4x + 21/4
0 = -3/4x + 21/4
3/4x = 21/4
x = 21/4 * 4/3
x = 84/12 = 7.....so ur x int is (7,0)
so plot ur points (7,0) and (0,5.25)....now start at (0,5.25) and since the slope is -3/4, come down 3 spaces and go to the right 4 spaces, then down 3, and to the right 4 and u will eventually cross the x axis at (7,0)