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polet [3.4K]
2 years ago
9

What is the surface area of the right cylinder below?

Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
7 0

Answer:

cant say you dont show

Step-by-step explanation:

id love to help but like send a picture next time

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4x - 22 = 62 + 2x<br> 15 points
k0ka [10]

4x-22=62+2x

4x-2x=62+22

2x=84

x=84/2= 42

x= 42 is the answer

4 0
3 years ago
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For what value of a is the equation an identity? a(2x + 3) = 9x + 15 + x
saul85 [17]
The answer to the question

4 0
3 years ago
My question is that fourty-one plus eighty-four equals what?
ivann1987 [24]

Answer:

41+84=125 so therefore your answer is 125.

5 0
3 years ago
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Someone please helpp
umka2103 [35]

Answer:

The two equations are similar because they both end up with the same common value. 0=0 The work you need to show that this is correct will be shown below.

Step-by-step explanation:

2(5m−4)−3(m−5)2=−3m2+40m−83

Add 3m^2 to both sides.

−3m2+40m−83+3m2=−3m2+40m−83+3m2

40m−83=40m−83

Subtract 40m from both sides.

40m−83−40m=40m−83−40m

−83=−83

−83+83=−83+83

0=0

If you have any questions regarding my answer please tell me in the comments, I will come and answer them. Have a good day.

6 0
3 years ago
1)Circle 1 is centered at (−4, 5)(−4, 5) and has a radius of 2 centimeters. Circle 2 is centered at (2, 1)(2, 1) and has a radiu
galina1969 [7]

Figures of same shape and size are similar .Two circles  C1&C2 will be similar.

Circle 1 has a center of (-4,5) and circle 2 has a center of (2,1) .The x of the center is having the translation x+6 and the y  is having a translation of y-4.The center of the circle is dilated by 3 units.

The circles are similar because you can translate Circle 1 using the transformation rule (x+6,y-4 ) and then dilate it using a scale factor of 3.

2) Area of sector = \pi.r^{2}\alpha÷360.

Where α is the angle made at center.

Area of given sector= π(12)(12)(60)÷360 =24π.

8 0
3 years ago
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