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3 years ago

HELP !!! will give brainliest. must show work so i know what to do next time :)))

Mathematics

1 answer:

WINSTONCH [101]3 years ago

3 0

Answer:

number 2

Step-by-step explanation:

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On a number line, which fraction is to the right of 3 5 ? A) 1 8 B) 3 12 C) 6 10 D) 3 4

Nikitich [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

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Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

The length of the shadow of a building is 100 meters

podryga [215]

Check the picture below.

make sure your calculator is in Degree mode.

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3 years ago

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2x^2-13x+20=2x <br> 2<br> −13x+20

marta [7]

Answer:

Factor by grouping

( 2 x + 5 ) ( x + 4 )

6 0

3 years ago

agasfer [191]

The slope intercept form is $y=5x-3$

Explanation:

The equation is $5 x-y=3$

Now, we shall bring the equation $5 x-y=3$ in the slope intercept form.

The general form of the slope intercept is given by

$y=mx+c$

Hence, we need to rewrite the given equation in this form.

Thus, we have,

$5 x-y=3$

Subtracting both sides of the equation by 5x, we get,

$-y=-5x+3$

Multiplying both sides of the equation by (-), we get,

$y=5x-3$

Thus, the slope intercept form of the given equation is $y=5x-3$

7 0

3 years ago