Answer:
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone ≈ 12.57 m²
Step-by-step explanation:
The given parameters are;
The height of the cone = 5 m
The base radius of the cone = 2 m
The angle which the AC = 120°
Therefore, we have;
The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone
The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°
∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57
The area of the base of the cone ≈ 12.57 m².
3. A square is a rhombus in which all the angles equal (to 90°).
4. 20 : 24 ratio that the ball picked wont be green
5. false
11. 15
12. half a chance (1/2)
13. 51
16. 9.79 × 10^-5
17. 4y = 29
18. b) 6.1
19. 80
20. x = -8/7
30. Area ≈ 7982.79
34. check the picture i attached for the histogram
THIS TOOK SO LONG
Answer:
Step-by-step explanation:
Given that X the time to complete a standardized exam in the BYU-Idaho Testing Center is approximately normal with a mean of 70 minutes and a standard deviation of 10 minutes.
We have 68 rule as 2/3 of total would lie within 1 std deviation, and 95 rule as nearly 95% lie within 2 std deviations from the mean.
We have std deviation = 10
Hence 2 std deviations from the mean
= Mean ±2 std deviations
=±20
=
Below 50, 0.25 or 2.5% would complete the exam.
Answer:
16 m²
Step-by-step explanation:
8 • 2 = 16
