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tekilochka [14]
3 years ago
7

A heap of grain is shaped as a cone ADCF with height 5 m and base radius 2 m, as shown on the diagram. A and C are points on the

circumference of the circular base of the cone and = 120°. Find:
a. the angle between [A F] and the base of the cone

Mathematics
1 answer:
hoa [83]3 years ago
8 0

Answer:

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone ≈ 12.57 m²

Step-by-step explanation:

The given parameters are;

The height of the cone = 5 m

The base radius of the cone  = 2 m

The angle which the A\hat OC = 120°

Therefore, we have;

The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone

The angle between [CF]  and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°  

∴ The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone = 68.2°

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57

The area of the base of the cone ≈ 12.57 m².

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the length of a swimming pool is 22 ft. the width is 40 ft. if the volume of the pool is 2,500 ft, which equation would you use
pochemuha
As we know that volume is three dimensional so we will multiply width, length and depth 
Now as we have to find the depth of the pool so
Volume= length*width*depth
depth=Volume/(length*width)
d=2500/(40*22)
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7 0
4 years ago
A distributor of personal computers has five locations in a city. In the year's first quarter, the sales in units were: Location
Deffense [45]

Answer:

The correct option is (c) 13.277.

Step-by-step explanation:

The observed data is:

Location                      Observed sales (units)

Northside                                70

Pleasant Township                 75

Southwick                               70

I-90                                          50

Venice Avenue                       35

TOTAL                                   300

The test statistic for the Goodness of fit test is:

\chi^{2}=\sum\frac{(Observed-Expected)^{2}}{Expected}

For <em>k</em> independent samples this test statistic follows a Chi-square distribution with degrees of freedom (<em>k</em> - 1).

The sample size in this case is, <em>k</em> = 5.

The degrees of freedom is, (<em>k</em> - 1) = 4.

The level of significance is, <em>α</em> = 0.01.

The critical value of the test is:

\chi^{2}_{\alpha ,k-1}=\chi^{2}_{0.01,4}=13.277

**Use the Chi-square table.

Thus, the critical value is 13.277.

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A candy company used 8 pints of chocolate to
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Answer:

They would need 24 pints of chocolate to make 6 boxes of candy

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The length of the table is 9 feet . Express the length in inches
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the length of the table is 108 inches

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