$11.13-$5.50-$6.12=$10.51; $30- $10.51
1 answer:
You might be interested in
So, I came up with something like this. I didn't find the final equation algebraically, but simply "figured it out". And I'm not sure how much "correct" this solution is, but it seems to work.
Answer:
Critical value: b. 2.33
As the test statistic z=7.17 is greater than the critical value, it falls in the rejection region.
The null hypothesis is rejected.
There is enough evidence to support the claim that the proportion of women who think sexual harassment is a major problem in the American workplace is significantly higher than the proportion of men.
Step-by-step explanation:
This is a hypothesis test for the difference between proportions.
The claim is that the proportion of women who think sexual harassment is a major problem in the American workplace is significantly higher than the proportion of men.
Then, the null and alternative hypothesis are:
The significance level is 0.01.
The sample 1 (women), of size n1=150 has a proportion of p1=0.62.
The sample 2 (men), of size n2=200 has a proportion of p2=0.24.
The difference between proportions is (p1-p2)=0.38.
The pooled proportion, needed to calculate the standard error, is:
The estimated standard error of the difference between means is computed using the formula:
Then, we can calculate the z-statistic as:
The critical value for a right-tailed test with a signficance level of 0.01 is zc=2.33 (see picture attached).
As the test statistic z=7.17 is greater than the critical value, it falls in the rejection region.
The null hypothesis is rejected.
There is enough evidence to support the claim that the proportion of women who think sexual harassment is a major problem in the American workplace is significantly higher than the proportion of men.
