Answer:
Yes it is a function
Step-by-step explanation:
We have to check the ordered pairs to find out if given relation is a function or not.
In an ordered pair, the first element represents the input and the second element represents the output.
The set of inputs is domain and output is range.
For a relation to be function, there should be no repetition in domain i.e there should be unique pairs of input and output.
In the given relation, the domain is {3,5,-1,-2}.
No element is repeated hence it is a function ..
Answer:
-6<x<0
- -
Step-by-step explanation:
make them less than or equal to signs, I don't know how to do that on a computer, I hope I am correct
point one on the left is -6, point 2 on the right is 0 (in terms of the x-axis, that's what domain is )
when there is arrows in the graph, the x/y is always in the middle.
Good luck! Hope I'm not late!
Answer:
Step-by-step explanation 10 + 2.50d = 850
David starts with $10 and each day he earns $2.50. The d represents a variable and can be any number.
To find d you must solve the equation.
10 + 2.50d = 850
2.50d = 840 (subtract 10 from 850)
d = 336 (divide 840 by 2.50)
It will take David 336 days to save $850.
Answer:
Step-by-step explanation:
1) P= Area of Circle/ Area of large rectangle
Area of the circle = pi·r² = pi·2²=4 pi ft.²
Area of large rectangle= l·w -12·10 =120 ft.²
P = 4pi/120 rewrite 120 as 4·30
P= 4 pi/4*30 = pi/30 = 3.14/40 ≈ .1047 ≈10% (because .1047·100 =10.47≅10)
2) P = Area of smaller rectangle/ Area of large rectangle
Area of smaller rectangle = l·w = 2·4 =8 ft.²
Area of large rectangle=l·w = 12·10=120 ft²
P= 8/120 ≅ .0666≅ 7% (because .0666·100 =6.66≅7)
3) P= Not the circle or smaller rectangle/ Area of large rectangle
Not the circle or smaller rectangle area
= Area of large rectangle - Area of circle -Area of smaller rectangle
= 120 -4·pi -8 = 120 - (4· 3.14) -8 = 99.4362939 ft²
Area of large rectangle = l·w = 12·10 =120 ft²
P = 99.4362939 /120 ≅ .8286 ≅83% (because .8286·100 =82.86≅83)
Answer:
1200 ml per hour
Step-by-step explanation:
To compute what rate is 300 ml over 15 mins as a rate of ml per hour, we do a rule of 3, using a variable x as that amount of ml we don't know yet. We should have everything in the same units, so instead of writing 1 hour we write 60 minutes:
Now we solve for x:
And so, now that we know the value of x, the rate we wanted to find is
Which is just 1200 ml per hour.
