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Margaret [11]
3 years ago
6

Simplify. n 6 · n 5 ÷ n 4 · n 3 ÷ n 2 · n

Mathematics
2 answers:
trasher [3.6K]3 years ago
7 0

Answer: n^{9}

Step-by-step explanation:

Given expression: n^6\cdot n^5\div n^4\cdot n^3\div n^2\cdot n

The law of exponents are given by :_

a^m\cdot a^n=a^{m+n}\\\\a^m\div a^n=a^{m-n}

Using PEDMAS, first we solve division, we get

n^6\cdot n^{5-4}\cdot n^{3-2}\cdot n\\\\=n^6\cdot n\cdot n\cdot n

Now, using product law of exponent we get

n^{6+1+1+1}\\\\=n^{9}

kakasveta [241]3 years ago
6 0

Answer:

The given expression  n^6\cdot n^5\div n^4\cdot n^3\div n^2\cdot n is n^9            

Step-by-step explanation:

Given : Expression  n^6\cdot n^5\div n^4\cdot n^3\div n^2\cdot n

We have to write the simplified form for the given expression  n^6\cdot n^5\div n^4\cdot n^3\div n^2\cdot n

Consider the given expression  n^6\cdot n^5\div n^4\cdot n^3\div n^2\cdot n

Rewrite it in simpler form, we have,

n^6\cdot\frac{n^5}{n^4}\cdot \frac{n^3}{n^2}\cdot n

Apply exponent rule, \:a^b\cdot \:a^c=a^{b+c}, we have,

n^6n=\:n^{6+1}

=\frac{n^5}{n^4}\cdot \frac{n^3}{n^2}n^{7}

Apply exponent rule, \frac{x^a}{x^b}=x^{a-b}

\frac{n^5}{n^4}=n^{5-4}

\frac{n^3}{n^2}=n^{3-2}

Expression becomes,

=n^7nn

Again apply exponent rule, we have,

\:a^b\cdot \:a^c=a^{b+c}

=n^{1+1+7}=n^9

Thus, The given expression n^6\cdot n^5\div n^4\cdot n^3\div n^2\cdot n is n^9

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Step-by-step explanation:

Given that:

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∴

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The upper limit = ( \overline x_1 - \overline x_2) + (M.O.E)

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= -20.1 + 2.52

= -17.58

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