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Arturiano [62]
3 years ago
7

PLEASE HELP ME WITH THIS!!

Mathematics
1 answer:
Natali5045456 [20]3 years ago
8 0
The first 2 are a function and the last 2 are not
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3 years ago
In parallelogram ABCD, AD = 12 in, m∠C = 46º, m∠DBA = 72º. Find the area of ABCD
dmitriy555 [2]

Answer:

The area of   parallelogram ABCD  is78.42 \mathrm{in}^{2}

Explanation:

Given:

AD = 12 in

m \angle C=46^{\circ}

m \angle D B A=72^{\circ}

To Find:

The area of   parallelogram ABCD=?  

Solution:

When we construct the parallelogram with the given data, we get a parallelogram formed by 12 cm as one side and an angle with 46 degrees.  

The area of the parallelogram can be calculated by a b * \sin (a n g l e)

Substituting the value of a=12  we have

\text { Area of parallelogram }=12 * \text { bsin } 46

<u>To find  the value of b, </u>

We know that area of a triangle can be expressed as,

\text { Area of triangle }=(A b / 2) \sin (\text {angle})

So,

(12 * B D / 2) * \sin 46=(A B * B D / 2) * \sin 72

Cancelling BD and 2 on both sides we get,  

12 * \sin 46=A B * \sin 72

A B=12 * \frac{\sin 46}{\sin 72}

Therefore,

b=\frac{12 \sin 46}{\sin 72}

Substituting the value of b,

=12 *\left(\frac{12 \sin 46}{\sin 72}\right) * \sin 46

=78.42  

So the area of the parallelogram is78.42 \mathrm{in}^{2}

6 0
4 years ago
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Vladimir79 [104]
He could be 40321 years old.
If you divide 40321 by any odd or even number between 1 and 9, the remainder is 1.

I got this number by doing (2*3*4*5*6*7*8) + 1
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315. You just need to take the total and subtract by 60.
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HELLPPPPP PLEASEEE HURRY FIND THE SURFACE AREA OF THE PYRAMID
mixas84 [53]

Answer:

8?

Step-by-step explanation:

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