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3 years ago

Can you help me with this please

Mathematics

1 answer:

Luda [366]3 years ago

7 0

I can as long as you show the questiom

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Find the zeros of the quadratic function: y= 6(7x + 9)(8x - 3).

fiasKO [112]

Answer:

A) (-9/7,0), (3/8,0)

Step-by-step explanation:

Zeros of a quadratic function:

x for which y = 0.

In this question:

$y = 6(7x + 9)(8x - 3)$

It's 0 if one of the factors is 0. 6 is never 0, now about the other to:

$7x + 9 = 0$

$7x = -9$

$x = -\frac{9}{7}$

So (-9/7, 0) is a zero of the quadratic function.

The other is:

$8x - 3 = 0$

$8x = 3$

$x = \frac{3}{8}$

(3/8,0) is the other zero.

Thus, the correct answer is given by option A.

6 0

2 years ago

Which system of equations intersect at point A in this graph y = 10x - 1

scZoUnD [109]

Its the first one i think

8 0

2 years ago

Read 2 more answers

3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

7 0

2 years ago

Helppppppppppp plzzz

Basile [38]

Answer:

Step-by-step explanation:

hope this helps......

8 0

2 years ago

ANSWER ASAPPP In 2000, the population of St. Louis was 346,904, and it decreased to 319,257 in 2010. If this population decre

mart [117]

Answer:

The y-intercept should be 346,904. This is the population for the first (first/last( known year of data. The year 2000 acts as 0 on the graph of the exponential function.

Step-by-step explanation:

I just did it on my homework and it said that my answer is right

8 0

2 years ago