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tekilochka [14]
3 years ago
13

You decide to eat out at the yarbird your bill that is pictured below shows that your food and beverage total is $45.00 server

was excellent and you decide to tip your waiter 20% how much do you leave for a tip
Mathematics
1 answer:
Arlecino [84]3 years ago
3 0
I don’t know I’m sorry
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Explain why P(A|D) and P(D|A) from the table below are not equal.
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Answer:

The Probability that Event A and  Event D occur is equal to the probability Event A occurs times the probability that Event D occurs, given that A has occurred.


P(A\cap D)=P(A)\cdot P(D/A)

We can find the values of P(A/D) and P(D/A) using the above form formula.

P(D/A)=\frac{P(A\cap D)}{P(A)} ;

P(A/D)=\frac{P(D\cap A)}{P(D)}

From the given table, we have the values of P(A), P(D), P(D\cap A) and P(A\cap D).

Since, Probability=\frac{The number of wanted outcomes }{the number of possible outcomes}

∴P(A)=\frac{8}{17}, P(D)=\frac{10}{17}, P(A\cap D)=\frac{2}{17} and P(D\cap A)=\frac{2}{17}

Now, putting these values in above formula we get,

P(D/A)=\frac{\frac{2}{17}} {\frac{8}{17}}

P(D/A)=\frac{2} {8}=\frac{1}{4}

P(D/A)= \frac{1}{4}.

P(A/D)=\frac{\frac{2}{17}} {\frac{10}{17}}=\frac{2}{10}

P(A/D)=\frac{1}{5}

As, you can see above that the values of P(A|D) and P(D|A) are not equal.









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3 years ago
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For 300 trading​ days, the daily closing price of a stock​ (in $) is well modeled by a Normal model with mean ​$196.99 and stand
KATRIN_1 [288]

Answer:

a) 2.5% b) 84% c) 95% d) D. The more unusual day is if the stock closed below $185 because it has the largest absolute z-score.

Step-by-step explanation:

For a) b) and c) we will use the empirical rule, so, we can observe the image shown below

a) 211.23 is exactly two standard deviation above the mean, so, the probability that on a randomly selected day in this period the stock price closed above 211.23 is 2.35% + 0.15% = 2.5%  

b) 204.11 represents exactly one standard deviation above the mean, so, the probability of being below 204.11 is 50% + 34% = 84%

c) The probability of getting a value between 182.75 and 211.23 is 95%, this because 182.75 is exactly two standard deviations below the mean and 211.23 is exactly two standard deviations above the mean.

d) The z-score related to 208 is z_{1} = (208-196.99)/7.12 = 1.5 and the z-score related to 185 is  z_{2} = (185-196.99)/7.12 = -1.7, therefore, the more unusual day is if the stock closed below $185 because it has the largest absolute z-score.

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