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ICE Princess25 [194]
2 years ago
5

Question 5 of 30 What is the period of the graph of y 5cos(4x – 1) + 3?

Mathematics
1 answer:
Anastaziya [24]2 years ago
8 0

Answer:

Period is \frac{\pi}{2}

Step-by-step explanation:

For the function y=acos(bx-c)+d, the period is \frac{2\pi}{|b|}.

Therefore, the period of the function is \frac{2\pi}{|b|}=\frac{2\pi}{|4|}=\frac{2\pi}{4}=\frac{\pi}{2}.

What this means is that the function's wave cycle will repeat every \frac{\pi}{2} units.

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To find 5, Beau found 22 = 4 and 32 = 9. He said that since 5 is between 4 and 9, 5 is between 2 and 3. Beau thinks a good estim
shusha [124]

Complete question

To find \sqrt{5} , Beau found 2^2 = 4 and 3^2 = 9 . He said that since 5 is between 4 and 9, \sqrt{5}, is between 2 and 3. Beau thinks a good estimate for \sqrt{5} , is \frac{2 + 3}{2} =  2.5 Is his estimate high or low? How do you know?

Answer:

The estimation is high because 5 is very close to 4 so \sqrt{5} will also be very close to \sqrt{4} which is lower than the estimate

In order to get a good estimate

The first step is to choose a number between 2 and 3 let say 2.8 , 2,85 , 2.9 and the square them

i.e

2.1^2 =  4.41

     2.2^2 =  4.84

      2.3^2 =  5.29

From here we can see that \sqrt{5}  lies between 2.2 and 2.3 but is closer to  2.2

So a good estimate for \sqrt{5} is 2.2

Step-by-step explanation:

8 0
3 years ago
A store sold $115.50 worth of coffee mugs how many mugs did the sell ?
viktelen [127]
Not enough information to actually do the problem, please provide more.
8 0
3 years ago
Read 2 more answers
Help what do I put in the table ignore the other question
givi [52]

Answer:

4.5, 4, 3.5, 3, 2.5, 2

Step-by-step explanation:

8 0
3 years ago
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2,−3) B(4,−3) C(4,5) D(2,5
AveGali [126]

Answer:

21 unit square

Step-by-step explanation:

First you want to find the length and width of the rectangle using the distance formula:

d=√(x2-x1)²+(y2-y1)²

AB=√(6-3)²+ (-2 - -2)²

AB=√3² + 0

AB=√9

AB=3

BC=√(6-6)²+ (5 - -2)²

BC=√0 + 7²

BC=√49

BC=7

We can find the area by multiplying these two distances together:

A=(3)(7)

A=21 units square.

Hope it helped...... And plz mark BRAINLIEST

Tysm

7 0
3 years ago
सुमित्रानन्दन पन्त<br>(जीवनकाल : सन् १९००-१९७७ ई०)​
Nataly_w [17]

Answer:

What is that?

Step-by-step explanation:

5 0
3 years ago
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