To do this problem, add up all the numbers and divide by the amount of numbers:

1.01+1.03+.98+.99+1.01+1.02+.98+1.05+.97+.98
10.02

Now divide by 10 (the amount of samples)

10.02/10
1.002

The Mean of the Data Set is 1.002

Hope this helps!

8 0

3 years ago

Read 2 more answers

How many times does 25 go into 63

statuscvo [17]

Answer:

2 times

Step-by-step explanation:

25 x 2 is 50. And 25 x 3 is 75, and 75 is larger then 63.

5 0

3 years ago

If x>2, then x^2-x-6/x^2-4=

Viefleur [7K]

Consider the expression $\frac{x^{2} -x-6}{ x^{2} -4}$

To factorize the expression in the denominator we use difference of squares: $x^{2} -4=x^{2} - 2^{2} =(x-2)(x+2)$

To factorize $x^{2} -x-6$ we use the following method:

$x^{2} -x-6=(x-a)(x-b)$

where a, b are 2 numbers such that a+b= -1, the coefficient of x,

and a*b= -6, the constant.

such 2 numbers can be easily checked to be -3 and 2

(-3*2=6, -3+2=-1)

So $x^{2} -x-6=(x-a)(x-b)=(x+3)(x-2)$

$
 \frac{x^{2} -x-6}{ x^{2} -4}= \frac{(x+3)(x-2)}{(x-2)(x+2)}= \frac{x+3}{x+2}$

$\frac{x+3}{x+2}= \frac{x+2+1}{x+2}= \frac{x+2}{x+2}+ \frac{1}{x+2}=1+ \frac{1}{x+2}$

for x>2

$\frac{1}{x+2}\ \textless \ \frac{1}{2+2}= \frac{1}{4}$

thus

for x>2,

$1+ \frac{1}{x+2}\ \textless \ 1+ \frac{1}{4}= \frac{5}{4}$

Answer:

for x>2

$\frac{x^{2} -x-6}{ x^{2} -4} = \frac{x+3}{x+2} \ \textless \ \frac{5}{4}$ , (but the expression is never 0)

8 0

3 years ago

Please help! i do not understand my homework!​

Please help! i do not understand my homework!