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sweet-ann [11.9K]
3 years ago
11

Round 4802 to the lead digit

Mathematics
1 answer:
Lelechka [254]3 years ago
8 0

Answer:

It would be 5000

Step-by-step explanation:

It would be 500 b/c the number is a greater number that is 4802 and it is closer to 5000 than 4000

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Answer:

- 3 + 3 = 0 - 3 =  - 3 \\  - 3 + 3 = 0 - 3 =  - 3 \\  - 3 + 3 = 0

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PLEASE HELP ME WHAT AM I SUPPOSE TO DO?!
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Answer:

Step-by-step explanation:

Angle 2= 50

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What is the answer for 3.7-4.2n-3n+8
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Llana [10]

a) The given function is

f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}

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This implies that;

x\ne -2.69,x\ne 1.83

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

x^4+x^3-4x^2-4=0

This implies that;

x= -2.69,x=1.83

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

\frac{x^2-4}{x^4+x^3-4x^2-4}=0

\Rightarrow x^2-4=0

x^2=4

x=\pm \sqrt{4}

x=\pm2

The roots are x=-2,x=2

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

x=0 into the function

f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}

f(0)=\frac{-4}{-4}=1

e) to find the horizontal asypmtote, we take limit to infinity

lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0

The horizontal asymtote is y=0

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is  at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

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