3 years ago

Help me please the picture below has the question and the answers

Mathematics

1 answer:

andrezito [222]3 years ago

6 0

Answer:

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try mo magsagot

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An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the objects maximum height if the equati

Free_Kalibri [48]

Max height is the vertex
convert to vertex form (y=a(x-h)^2+k) by completeing the square

h(t)=-16(t²-4t)+80
h(t)=-16(t²-4t+4-4)+80
h(t)=-16((t-2)²-4)+80
h(t)=-16(t-2)²+64+80
h(t)=-16(t-2)²+144

vertex is (2,144)
at t=2, the height is 144

max height is 144ft

4 0

3 years ago

I’ll mark Brainliest if correct ||question: which of the following shows the correct evaluation for the expression (2/5)^5

Nitella [24]

The 1st one

Well it's the same as normal exponents so you multiply 2/3 x 2/3 x 2/3 x 2/3 x 2/3

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3 years ago

Read 2 more answers

E-Z View cable company charges a flat rate of $40 per month for service and $4.95 for each pay per view movie. View the Best cha

kkurt [141]

E-Z View: 40 + 4.95x
View the best: 25 + 5.95x

Equal monthly bills:

40 + 4.95x = 25 + 5.95x

5.95x - 4.95x = 40 - 25

x = 15

Answer: 15