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3 years ago

Pls help With thissss

Mathematics

2 answers:

Grace [21]3 years ago

8 0

Answer:

Ion know lol

Step-by-step explanation:

Georgia [21]3 years ago

3 0

The answer is An estimate so it’s B

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HELP PYTHAGORAS THEOREM

finlep [7]

So the hypotenuse is the ladder's length, which is 6m, and the base of the 'triangle' is 1.5m. Therefore, you do 6^2 - 1.5^2 = 36 - 2.25 = 33.75. Then, you just square root it to get 5.80948m. Hope this helps!

4 0

4 years ago

Read 2 more answers

JUST CHECKING MY ANSWER JS THJS RIGHT? I’ll mark BRAINLIEST

tia_tia [17]

Answer:

I cant see the whole thing But I think you're right

4 0

3 years ago

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A Government company claims that an average light bulb lasts 270 days. A researcher randomly selects 18 bulbs for testing. The s

Fofino [41]

Answer:

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question, we have that:

$\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2$

What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?

This is the pvalue of Z when $X = 260$ . So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{260 - 270}{21.2}$

$Z = -0.47$

$Z = -0.47$ has a pvalue of 0.3192.

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

5 0

3 years ago

Courtney and Alan are conducting an experiment. Every time Courtney flips a fair two-sided coin, Alan rolls a six-sided die. Wha

Naily [24]

Answer:

I think the answer is D. 1/12

7 0

3 years ago

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The first term of a geometric sequence is −2 and the common ratio is 3. What is the fourth term of the sequence?

Nat2105 [25]

Answer: -54

Step-by-step explanation:

The question is the first term of a geometric sequence is −2 and the common ratio is 3. The formula for finding the nth term of a geometric sequence is: ar^n-1

where,

a = first term = -2

r = common ratio = 3

n = number of terms = 4

The solution has been attached. The answer is -54

5 0

3 years ago