Answer:
5,10; 6,12; 7,14
Explanation:
We will demonstrate the iteration of the loop:
First iteration: Number = 7, Count = 5 at the beginning. We will check if Count <= Number? Since it is correct, prints 5,10. Increment the Count by 1.
Second iteration: Number = 7, Count = 6. We will check if Count <= Number? Since it is correct, prints 6,12. Increment the Count by 1.
Third iteration: Number = 7, Count = 7. We will check if Count <= Number? Since it is correct, prints 7,14. Increment the Count by 1.
Forth iteration: Number = 7, Count = 8. We will check if Count <= Number? Since it is not correct, the loop stops.
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Answer:
The solution code is written in Python:
- def add_spaces(s):
- if len(s) < 2:
- return s
- else:
- return s[0] + " " + add_spaces( s[1 : ] )
Explanation:
Recursive function is a function that will call itself within the same function.
Let create a function named add_spaces() that take one input string, s (Line 1).
Next, create an if condition to check if the length of the input string is less than 2 (this means if the string has only one character), return the current string (Line 2-3).
Otherwise, it should return the first character of string, s[0] concatenated with a single space " " and concatenated again with the return output from the recursive calling add_spaces() that take s[1: ] as input parameter (Line 4-5). Please note s[1: ] is an expression we get the substring of the current string from position 1 till the end of string.