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3 years ago

11

find the length, width, area, and perimeter of a rectangle where the length is 5 units more than the width and the perimeter is

9 times the width

1 answer:

skad [1K]3 years ago

6 0

Step-by-step explanation:

L= W+5

P= 9W

P= 2L+ 2W

9W= 2(W+5) + 2W

9W= 2W +10 +2W

9W = 4W +10

5W = 10

W = 2

L=7

P= 9(2)

P= 18

A= LW

A= 7 x 2

A= 14

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Step-by-step explanation:

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Suppose that a function f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence

Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

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If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

$\lim_{x \to c} \frac{x^2-cx}{(x-c)}$

We can simplify it

$\lim_{x \to c} \frac{x(x-c)}{(x-c)}$

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case-2:

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4 0

3 years ago

Can anyone help please

NeTakaya

Answer:

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Step-by-step explanation:

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3 years ago

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garik1379 [7]

Answer:The number of nickles is 6

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Step-by-step explanation:

Given as :

Sum of total number of dims and nickels coins = 18

The value of total combination = $1.50

Let The total number of dims = d

Let The total number of nickels = n

1 nickles = $0.05

1 dims = $0.1

According to question

Total number of dims and nickels coins = number of dims + number of nickels

Or, d + n = 18 .........1

And

$0.1 ×d + $0.05 ×n = $1.50

Or, 0.1 d + 0.05 n = 1.50 .........2

Now, Solving eq 1 an eq 2

0.1 × (d + n) - (0.1 d + 0.05 n) = 0.1 × 18 - 1.50

Or, (0.1 d - 0.1 d) + (0.1 n - 0.05 n) = 1.8 - 1.50

Or, 0 + 0.05 n = 0.3

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So, The number of dims = d = 12

Hence, The number of nickles is 6 and the number of dims is 12 .

Step-by-step explanation:

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3 years ago