Answer:
lj= lk din 30 give lj= 4✓2
and ml=x= lj cos 45
on solving x= 4✓2 cos45=4
Using the normal distribution, it is found that 0.26% of the items will either weigh less than 87 grams or more than 93 grams.
In a <em>normal distribution</em> with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 90 grams, hence
.
- The standard deviation is of 1 gram, hence
.
We want to find the probability of an item <u>differing more than 3 grams from the mean</u>, hence:



The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.
- Looking at the z-table, Z = -3 has a p-value of 0.0013.
2 x 0.0013 = 0.0026
0.0026 x 100% = 0.26%
0.26% of the items will either weigh less than 87 grams or more than 93 grams.
For more on the normal distribution, you can check brainly.com/question/24663213
Answer:
5/20, 2/9, 21%, 8%
Step-by-step explanation:
2/9 = 0.22
21% = 0.21
5/20 = 0.25
8% = 0.08
0.25>0.22>0.21>0.08
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Answer:
The answer is -9,9 Its funny cuz I just did this problem on Khan academy
Step-by-step explanation:
Can I get brainliest
Answer:1) In Δ FGH,
FH=7 ft, FG=12 ft,
∠F=70 degrees
By "Law of cosines":
So,By applying Law of Sines , we get that
Hence, Option 'D' is correct.
2) In Δ XYZ,
XY=14, ∠Y=22°, and XZ=26
By using "Law of sines":
so, X = 147° , Y = 22° , Z = 11.6°
Step-by-step explanation: