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Bumek [7]
3 years ago
11

find the length, width, area, and perimeter of a rectangle where the length is 5 units more than the width and the perimeter is

9 times the width

Mathematics
1 answer:
skad [1K]3 years ago
6 0

Step-by-step explanation:

L= W+5

P= 9W

P= 2L+ 2W

9W= 2(W+5) + 2W

9W= 2W +10 +2W

9W = 4W +10

5W = 10

W = 2

L=7

P= 9(2)

P= 18

A= LW

A= 7 x 2

A= 14

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Answer and Step-by-step explanation:

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Since the hypothenuse is 50, we can test each statement by taking the square of the two sides and add them up, if they are equal to 50² = 2500, then the statement is true.

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