What is the volume of a hemisphere with a diameter of 56.7 in, rounded to the
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The area of the field where the length of each side is increased by 10% is 48.4 .
Step-by-step explanation:
The given is,
A rectangle field has an area of 40
If one side of the field is 3 cm longer than the other side
The length of new area in each side is increased by 10%
Step:1
Let,
- One side of rectangle
- Other side of rectangle
From given.
-
+3
Formula for area of rectangle,
40 = ( b+3) × b
40 = + 3b
Solving the above the equation,
b = 5 cm
l = 8 cm
Step:2
If the area of rectangle increased by 10%,
l = 8 + ( 8 × )
= 8.8
b = 5 + ( 5 × )
= 5.5
Area of rectangle is,
a = ( 8.8 × 5.5 )
= 48.4 square centimeters
Result:
The area of the field where the length of each side is increased by 10% is 48.4 , if a rectangle field has an area of 40 square centimeters and one side of the field is 3 cm longer than the other side.