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3 years ago

Please can anyone help?

Mathematics

1 answer:

Elena L [17]3 years ago

7 0

Answer:

9/5x^3

Step-by-step explanation:

i hope that is the answer

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This is confusing i need help ;-;

katovenus [111]

Answer:

B I think

Step-by-step explanation:

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3 years ago

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Which expressions is equivalent to (x+2)(3x-3)

max2010maxim [7]

Answer:

Step-by-step explanation:

(x+2)(3x-3)

= 3x^2 -3x + 6x - 6

= 3x^2 + 3x - 6

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3 years ago

Which two equations would be represented as parallel lines?

Mariana [72]

Answer:

The first and third options are parallel.

Step-by-step explanation:

They both have a slope of 2.

Pls mark brainliest. Thanks!

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3 years ago

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Zac is 4 years older than Bethany. The sum of their ages is 46. How old is Zac?

anygoal [31]

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Step-by-step explanation:

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3 years ago

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago