We have that
f²{k^6/[k^4*k^3]}^-3
step 1
f²{k^6/[k^(4+3)]}^-3---------> f²{k^6/[k^7]}^-3-------> step 1 is correct
step 2
f²{k^6/[k^7]}^-3------> f²{k^(6-7)]}^-3----> f²{k^(-1)}^-3----> step 2 is correct
step 3
f²{k^(-1)}^-3------> f²{k^[(-1)*(-3)]}-----> f²{k^(3)}
therefore
Martha made a mistake in the step 3
the answer is
step 3
f²k³
4x + y = 5
3x + y = 8
y = -3x + 8
4x +(-3x + 8) = 5
4x -3x + 8 = 5
x + 8 = 5
x = -3
y = -3(-3) + 8
y = -9 + 8
y = -1
The answer to your question is 48-x
<span>The least common multiple of 6 and 10 is 30. </span>
Answer:
$90
Step-by-step explanation:
9 times 10 is 90
