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Tju [1.3M]
2 years ago
7

Can somebody please help me !!!!!!!!!47$4&

Mathematics
2 answers:
Andrews [41]2 years ago
5 0

Answer:

30 celsius

Step-by-step explanation:

(86°F − 32) × 5/9 = 30°C

steposvetlana [31]2 years ago
4 0
its 30 celsius! hope this helps:)
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Simplify (4s5t−7−2s−2t4)3. Write your answer using only positive exponents. Evaluate any numerical powers.
schepotkina [342]

Answer:

−21

Step-by-step explanation:

=12s5t−6t4−6s−21

5 0
3 years ago
Double the sum of x and 5
jolli1 [7]

Answer:

2(x+5) = 2x+10

Step-by-step explanation:

2(x+5)

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6 0
2 years ago
What is the solution set for the inequality 4−5g > 39 Question 3 options: g < −7 g>7 g<7 g > −7.
neonofarm [45]

Answer:

g < -7

General Formulas and Concepts:
<u>Algebra I</u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Terms/Coefficients

Step-by-step explanation:

*Note:

When dividing or multiplying both sides of the inequality by a negative, <em>flip</em> the inequality sign.

<u>Step 1: Define</u>

<em>Identify.</em>

4 - 5g > 39

<u>Step 2: Solve for </u><u><em>g</em></u>

  1. [Subtraction Property of Equality] Subtract 4 on both sides:                    -5g > 35
  2. [Division Property of Equality] Divide -5 on both sides:                              g < -7

∴ any number <em>g</em> less than -7 would work as a solution to the inequality.

---

Topic: Algebra I

Unit: Inequalities

8 0
2 years ago
Find the value of x, rounded to the nearest tenth. <br> Answer options: 3.8, 4, 2.7, 2.9
Masteriza [31]

Answer:

4

Step-by-step explanation:

If two chords intersect externally, then the product of the length of the chord and the length of the part outside the circle is a constant.

Thus from the figure,

we can deduce that:

8×3=6×x

collecting the like terms together we get:

24=6x

x=4

4 0
3 years ago
Read 2 more answers
What is the value of f(x)=-4 ?
Gala2k [10]
Answer : 2

Step by step walkthrough:
7 0
3 years ago
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