3 years ago

-absolute value-(-5^3)

Mathematics

2 answers:

Mamont248 [21]3 years ago

5 0

Answer:

5^3

Step-by-step explanation:

aev [14]3 years ago

5 0

Answer:

Step-by-step explanation:

multiply -3 x 5. then find distance from -15 from 0

You might be interested in

I need help with addition I think

kaheart [24]

Answer: $512 is your answer

8 0

3 years ago

Find the selling price of a computer if it costs $1,980 and it sold at a 4% loss.

Alika [10]

1980-1980^4%
=1980-79.2
=$1900.8

4 0

3 years ago

Jessica is 17 in five years her age will 5/2 the age of her sister

BlackZzzverrR [31]

Not sure, sorry!!!!!!!

6 0

3 years ago

Help finding derivative

marusya05 [52]

$\bf \displaystyle \cfrac{d}{dx}\left[ \int\limits_{\sqrt{x}}^{\frac{\pi }{2}}~[cos(t^2)]dt \right]\implies \cfrac{d}{dx}\left[ -\int\limits_{\frac{\pi }{2}}^{\sqrt{x}}~[cos(t^2)]dt \right]\\\\\\ \cfrac{d}{dx}\left[ -\int\limits_{\frac{\pi }{2}}^{x^{\frac{1}{2}}}~[cos(t^2)]dt \right]\\\\
-------------------------------\\\\
u=x^{\frac{1}{2}}\implies \cfrac{du}{dx}=\cfrac{1}{2\sqrt{x}}\\\\\\ \textit{and now, let's use the \underline{2nd fundamental theorem of calculus}}\\\\
-------------------------------\\\\$

$\bf \displaystyle \cfrac{d}{dx}\left[ -\int\limits_{\frac{\pi }{2}}^{u}~[cos(t^2)]dt \right]\impliedby \cfrac{df}{dx}=\cfrac{df}{du}\cdot \cfrac{du}{dx}
\\\\\\
\cfrac{df}{dx}=-cos(u^2)\cdot \cfrac{du}{dx}\implies \cfrac{df}{dx}=-cos(u^2)\cdot \cfrac{1}{2\sqrt{x}}
\\\\\\
\cfrac{df}{dx}=-cos[(\sqrt{x})^2]\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{df}{dx}=-\cfrac{cos(x)}{2\sqrt{x}}$

6 0

3 years ago

Today we are doing long divison and i really needthe extra help

GalinKa [24]

Answer:

57.5

Step-by-step explanation:

6 0

3 years ago

-absolute value-(-5^3)​

-absolute value-(-5^3)